我是ReactJS的新手,我真的很喜欢这个,所以请耐心等待。我想知道是否有办法使用react路由器向我的导航链接添加活动类。这就是我的代码看起来......
import React, { Component, PropTypes } from 'react';
import history from '../../core/history';
function isLeftClickEvent(event) {
return event.button === 0;
}
function isModifiedEvent(event) {
return !!(event.metaKey || event.altKey || event.ctrlKey || event.shiftKey);
}
class Link extends Component { // eslint-disable-line react/prefer-stateless- function
static propTypes = {
to: PropTypes.oneOfType([PropTypes.string, PropTypes.object]).isRequired,
onClick: PropTypes.func
};
handleClick = (event) => {
let allowTransition = true;
if (this.props.onClick) {
this.props.onClick(event);
}
if (isModifiedEvent(event) || !isLeftClickEvent(event)) {
return;
}
if (event.defaultPrevented === true) {
allowTransition = false;
}
event.preventDefault();
if (allowTransition) {
if (this.props.to) {
history.push(this.props.to);
} else {
history.push({
pathname: event.currentTarget.pathname,
search: event.currentTarget.search
});
}
}
};
render() {
const { to, ...props } = this.props; // eslint-disable-line no-use-before-define
return <a href={history.createHref(to)} {...props} onClick={this.handleClick} />;
}
}
export default Link;
import React, { PropTypes } from 'react';
import cx from 'classnames';
import withStyles from 'isomorphic-style-loader/lib/withStyles';
import s from './Navigation.css';
import Link from '../Link';
function Navigation({ className }) {
return (
<div className={cx(s.root, className)} role="navigation">
<Link className={s.link + ' fa fa-dribbble'} to="/dribbble"/>
<Link className={s.link + ' fa fa-behance' } to="/behance"/>
<Link className={s.link + ' fa fa-linkedin' } to="/linkedin"/>
<Link className={s.link + ' fa fa-twitter' } to="/twitter"/>
<Link className={s.link + ' fa fa-instagram' } to="/instagram"/>
<Link className={s.link + ' fa fa-vimeo' } to="/vimeo"/>
</div>
);
}
Navigation.propTypes = {
className: PropTypes.string
};
export default withStyles(s)(Navigation);
我想要做的是添加一个这样的活动类,例如:
<a class="link active">Home</a>
<a class="link">About</a>
<a class="link">Contact</a>
<a class="link">Work</a>
<a class="link">Support</a>
关于如何做到这一点的任何想法?我一直在搞乱反应,但我找不到一个简单的方法来做它..
答案 0 :(得分:2)
您可以更改活动链接的样式:
import React from 'react';
import { Router, Route, IndexRoute, Link, IndexLink, browserHistory } from 'react-router';
const ACTIVE = { background: '#286090', color: '#fff'}
// In your render
<li><Link to="/case" activeStyle={ACTIVE}>case</Link></li>
<li><Link to="/primarysource" activeStyle={ACTIVE}>primarysource</Link></li>
<li><Link to="/literature" activeStyle={ACTIVE}>literature</Link></li>
<li><Link to="/study" activeStyle={ACTIVE}>study</Link></li>
示例可以在react-router示例github https://github.com/reactjs/react-router/blob/master/examples/active-links/app.js
中找到答案 1 :(得分:1)
其实我在这里找到了答案
function Navigation({ className }) {
return (
<div className={cx(s.root, className)} role="navigation">
<Link className={cx(s.link, 'fa fa-dribbble', { 'active': location.pathname === '/dribbble' })} to="/dribbble" />
<Link className={cx(s.link, 'fa fa-behance', { 'active': location.pathname === '/behance' })} to="/behance" />
<Link className={cx(s.link, ' fa fa-linkedin', { 'active': location.pathname === '/linkedin' })} to="/linkedin" />
<Link className={cx(s.link, ' fa fa-twitter', { 'active': location.pathname === '/twitter' })} to="/twitter" />
<Link className={cx(s.link, ' fa fa-instagram', { 'active': location.pathname === '/instagram' })} to="/instagram" />
<Link className={cx(s.link, ' fa fa-vimeo', { 'active': location.pathname === '/vimeo' })} to="/vimeo" />
</div>
);
}
注意:这没有React Router
答案 2 :(得分:1)
我刚使用了activeClassName =&#34;有效&#34;
<Link to="/" activeClassName="active">
<i className="fa fa-tachometer" aria-hidden="true"></i><br/>Dashboard</Link>