Question

我想获取当前行和上一行之间的秒数差异，并在订单ID也使用google bigquery匹配时将值存储在单独的列中。 PS：第4行根据第7行获取差异，因为这是下一个可用的订单ID （在我的表test：product.tab1中，日期字段不是字符串而是时间戳）例如：

Date                    Order  Difference In Seconds
2016-05-31 11:46:54 UTC 14567   11
2016-05-31 11:46:43 UTC 14567   19
2016-05-31 11:46:24 UTC 14567   20
2016-05-31 11:46:04 UTC 14567    4
2016-05-31 11:46:54 UTC 22455   11
2016-05-31 11:46:43 UTC 24567    0
2016-05-31 11:46:00 UTC 14567    0

Answer 1

请尝试以下
我建议你查看Window functions

SELECT
  DATE, id,
  IFNULL(TIMESTAMP_TO_SEC(TIMESTAMP(DATE)) -   
         TIMESTAMP_TO_SEC(TIMESTAMP(prev_date))
    , 0) AS Difference_In_Seconds
FROM (
  SELECT  
    DATE, id,
    LEAD(DATE) OVER(PARTITION BY id ORDER BY DATE DESC) AS prev_date
  FROM
    (SELECT STRING(DATE) AS DATE, id FROM [test:product.tab1] )
)
ORDER BY id, DATE DESC

当前行和上一行之间的秒数差异，并且当订单ID也使用google bigquery匹配时，将值存储在单独的列中

1 个答案: