Question

您好，我如何将两个参数从片段传递给活动？我试着这样做，但我做不到。我只在TextView editRef中得到了ref，但TextView et_login是空的

public class ResultFragmentC  extends Fragment implements ListView.OnItemClickListener {
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
        View rootview = inflater.inflate(R.layout.fragment_result, container, false);
        et_login = (TextView) rootview.findViewById(R.id.et_login);
        Intent intent = getActivity().getIntent();
        String log = intent.getStringExtra("login");
        et_login.setText(log);
......

}
......

    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            Intent intent = new Intent(getActivity().getApplicationContext(), ViewResult.class);
            HashMap<String, String> map = (HashMap) parent.getItemAtPosition(position);
            String tid = map.get("ref");
            intent.putExtra("ref", tid);
            String tid2 = map.get("log");
            intent.putExtra("log", tid2);
            startActivity(intent);
        }

ViewResult.java

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.view_result);
        Intent intent = getIntent();
        layout=(LinearLayout) findViewById(R.id.layout);
        String ref2 = intent.getStringExtra("ref");
        et_login = (TextView) findViewById(R.id.et_login);
        String log = intent.getStringExtra("log");
        et_login.setText(log);
        editRef = (TextView) findViewById(R.id.editRef);
        editRef.setText(ref2);
}

Answer 1

仔细检查您是否正在使用相同的密钥进行意图。

Intent intent = getActivity().getIntent();
String log = intent.getStringExtra("login");

与

不一样

Intent intent = getIntent();
String log = intent.getStringExtra("log");

ViewResult.java中显示的内容应该与onItemClick假设map.get()没有回复null的内容有关。

应该提到的是，使用Activity意图并不是如何为Fragments提供参数。请参阅Best practice for instantiating a new Android Fragment。

我如何将两个参数从片段传递给活动

1 个答案: