Question

我有几个表...一个包含网站，另一个包含一些用户。有一个链接将特定用户绑定到特定站点。当我运行我的查询时：

select sites.site, users.fullname
from sites
inner join users
on sites.nameid = users.id;

我得到以下输出：

 SITE  | FULLNAME

site A | John Doe
site B | John Doe
site C | John Doe
site D | Roger Rabbit
site E | Roger Rabbit
site F | Batman

我正在寻找的是一个包含以下网站列表的FULLNAME：

  SITE | FULLNAME

site A | John Doe
site B
site C
site D | Roger Rabbit
site E
site F | Batman

我不知道这是否可能，或者我是否必须使用别的东西来获取我正在寻找的格式。

我将在这里添加一些我应该包含的更多细节....首先...我的查询已更改为：

    SELECT completed.date, users.username, iata.code, tasks.task 
FROM completed     
JOIN users         
ON users.id = completed.name     
JOIN iata         
ON iata.id = completed.code     
JOIN tasks         
ON tasks.id = completed.task
WHERE MONTH(completed.date) = MONTH(NOW()) AND YEAR(completed.date) = YEAR(NOW());

这给了我想要的一切......我用来显示的php / html看起来像这样：

<!DOCTYPE html>
<html>

   <head>
      <title>SPOC Report</title>
      <meta charset=utf-8>
   </head>

   <body>
        <?php 
        require 'db/spoc_config.php';
        ?>

        <?php

        $conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);

        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        }

        $sql_count = "
SELECT completed.date, users.username, iata.code, tasks.task 
FROM completed     
JOIN users         
ON users.id = completed.name     
JOIN iata         
ON iata.id = completed.code     
JOIN tasks         
ON tasks.id = completed.task
WHERE MONTH(completed.date) = MONTH(NOW()) AND YEAR(completed.date) = YEAR(NOW());
";  

        $result_count = $conn->query($sql_count);

        $count = mysqli_fetch_row($result_count);
        $str_count = implode($count);

         date_default_timezone_set('UTC');
         $today = date('l, jS F Y');
         $week = date('W');
         $to = "johndoe@me.com";
         $subject = "SPOC: Monthly Report " . $today;        
         $heading = "<b>SPOC Report: </b>";

         $message = "<h2>" . $heading . " " . $today . "</h2>"; 
         $message .= '<table style="font-family: verdana,arial,sans-serif;font-size:11px;color:#333333;border-width: 1px;border-color: #666666;border-collapse: collapse;border-spacing: 2px;">';
         $message .= '
         <th style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #dedede;">Spoc</th> 
         <th style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #dedede;">Site</th>
         <th style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #dedede;">Task</th>';

         if ($result_count->num_rows > 0) {
         while($row = $result_count->fetch_assoc()) {
         $message .= '<tr style="white-space: normal;line-height: normal;font-weight: normal;font-variant: normal;font-style: normal;text-align: start;">
          <td style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #ffffff;display: table-cell;vertical-align: inherit;">'.$row["username"].'</td>
          <td style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #ffffff;display: table-cell;vertical-align: inherit;">'.$row["code"].'</br></td>
          <td style="border-width: 1px;padding: 8px;border-style: solid;border-color: #666666;background-color: #ffffff;display: table-cell;vertical-align: inherit;">'.$row["task"].'</br></td>
          </tr>';
                }
            } else {
                echo "0 results";
            }
         $message .= '</table>';


         $header = "From:johndoe@me.com \r\n";
         $header .= "MIME-Version: 1.0\r\n";
         $header .= "Content-Type: text/html; charset=ISO-8859-1\r\n";

         $retval = mail ($to,$subject,$message,$header,'-fjohndoe@me.com');


         $conn->close();
        ?>     
   </body>
</html>

输出看起来像这样：

SPOC        | SITE   | TASK

JohnDoe     | SITE A | TASK1
JohnDoe     | SITE A | TASK2
JohnDoe     | SITE B | TASK1
JohnDoe     | SITE C | TASK1
ROGERRABBIT | SITE A | TASK1
ROGERRABBIT | SITE A | TASK2

我正在寻找的是：

JohnDoe     | Site A | TASK1, TASK2, TASK3
JohnDoe     | Site B | Task1, Task2
RogerRabbit | Site A | tASk1, Task2

希望这清楚一点。对不起那些人感到困惑。

Answer 1

这不完全是你想要的，但它可能有所帮助：

SELECT users.fullname, GROUP_CONCAT(sites.site ORDER BY sites.site SEPARATOR ', ') 
FROM sites 
LEFT JOIN users ON sites.nameid = users.id
GROUP BY users.id;

输出：

John Doe     | site A, site B, site C
Roger Rabbit | site D, site E
Batman       | site F

为了获得您想要的结果，我会在我的PHP脚本中执行此操作。

Answer 2

两个表中必须有一个主键列，例如USER ID，以便执行以下查询

select a.site,b.fullname from site a, users b where a.id = b.id

SQL查询显示一列和多个值

2 个答案: