我有2张门票和回复。
门票获得此字段: ID,dname,mname,subject,priority,message,date,last_reply,status,close_mname,cdfileds
回复得到此文件: id,tid,mname,message,date
这些表是支持票。 我想将表导出为CSV。 这是我使用的代码。
<?php
/* vars for export */
// database record to be exported
$db_record = 'trxp_tickets';
$db_record2 = 'trxp_replies'; // added by me
// optional where query
$where = 'WHERE 1 ORDER BY 1';
// filename for export
$csv_filename = 'db_export_'.$db_record.'_'.date('Y-m-d').'.csv';
// database variables
$hostname = "localhost";
$user = "xxxxx";
$password = "xxxxx";
$database = "xxxxxx";
// Database connecten voor alle services
mysql_connect($hostname, $user, $password)
or die('Could not connect: ' . mysql_error());
mysql_select_db($database)
or die ('Could not select database ' . mysql_error());
// create empty variable to be filled with export data
$csv_export = '';
// query to get data from database
$query = mysql_query("SELECT id,dname,mname,subject,priority,message,date,last_reply,status,close_mname,cdfields FROM ".$db_record." ".$where);
$field = mysql_num_fields($query);
// create line with field names
for($i = 0; $i < $field; $i++) {
$csv_export.= mysql_field_name($query,$i).';';
}
// newline (seems to work both on Linux & Windows servers)
$csv_export.= '
';
// loop through database query and fill export variable
while($row = mysql_fetch_array($query)) {
// create line with field values
for($i = 0; $i < $field; $i++) {
$csv_export.= '"'.$row[mysql_field_name($query,$i)].'";';
}
$csv_export.= '
';
}
// Export the data and prompt a csv file for download
header("Content-type: text/x-csv");
header("Content-Disposition: attachment; filename=".$csv_filename."");
echo($csv_export);
?>
在代码中,当我进行SELEC时,它不包含在第二个表中,对于双打结果。尝试使用UNION和UNION ALL但不起作用。 我想留在下面列出的每张票证回复中的CSV。
答案 0 :(得分:0)
更改SQL以从两个表中获取数据:
$query = mysql_query("SELECT
r1.id, r1.dname, r1.mname, r1.subject,
r1.priority, r1.message,
DATE_FORMAT(FROM_UNIXTIME(r1.date), '%d/%m/%Y') as r1_date,
r1.last_reply, r1.status, r1.close_mname,
r1.cdfields,
r2.id, r2.tid, r2.mname,
r2.message
DATE_FORMAT(FROM_UNIXTIME(r2.date), '%d/%m/%Y') as r2_date,
FROM ".$db_record." r1
INNER JOIN ".$db_record2." r2
ON r1.id = r2.tid
".$where.");
这应该可以解决问题。
不推荐使用mysql_ *函数。您应该更改为mysqli_ *或PDO。 (http://php.net/manual/en/function.mysql-query.php)