Question

以下是我的代码，但它不会生成唯一的随机数

Random rand = new Random();

int[] array = new int[n];

for (int i = 0; i < n; i++){
    array[i] = rand.nextInt(n)+1;
}


for (int i = 0; i < ( n - 1 ); i++)
{
    for (int j = 0; j < n - i - 1; j++) {
        if (array[j] > array[j+1]){
            int temp = array[j];
            array[j]   = array[j+1];
            array[j+1] = temp;
        }
    }
}

Answer 1

public TextView tv;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    tv=(TextView)findViewById(R.id.textView);

    Random r = new Random();

    StringBuffer temp =new StringBuffer("Random numbers:");
    for(int i=0;i<10;i++) {
        int i1 = r.nextInt(100 - 0) + 0;

        temp.append(String.valueOf(i1));
        temp.append(String.valueOf(" "));
    }
    tv.setText(temp.toString());
}
//here ,,I generate 10 random numbers and save it in to stringBuffer and dispaly it in to textView..here range is up to 0 to 100...you can take your own Range ...I hope ,,It will help you...

Answer 2

检查一下！...它对我有用

Random rand = new Random();

int n = 10;
int[] array = new int[n];

for (int i = 0; i < n; i++){
    array[i] = (int) (rand.nextDouble() * n + 1);
}


for (int i = 0; i < ( n - 1 ); i++)
{
    for (int j = 0; j < n - i - 1; j++) {
        if (array[j] > array[j+1]){
            int temp = array[j];
            array[j]   = array[j+1];
            array[j+1] = temp;
        }
    }
}

for (int piece: array) {
  System.out.println(piece);
}

Android：如何在数组中生成唯一的随机数并执行冒泡排序？

2 个答案: