Question

我想编写一个将显示为

的SQL查询

1）名称以“myTeam”

开头的每个组件

2）类型“Bug”

3）本月开了多少个错误，有多少错误来自该小组的后续词？

这是我的代码：

select 
histories.component_path,
count distinct bug_id as id1 from buganizer.metadata.latest WHERE (histories.component_path LIKE 'myTeam >%' And type_id = 'BUG' And (date - Now() < 30) ) as total_bugs,
count distinct bug_id as id2 from buganizer.metadata.latest WHERE (histories.component_path LIKE 'myTeam >%' And type_id = 'BUG' And status_id = 'VERIFIED') as verified_bugs

如何使这个缩短并更好地格式化？

Answer 1

我修改了你的查询，如下所示。 COUNT不会考虑NULL值。您可以尝试查询（未经验证）

SELECT  A.component_path, 
        COUNT(DISTINCT A.id1) AS total_bugs,
        COUNT(DISTINCT A.id2) AS verified_bugs
FROM (
    SELECT 
        histories.component_path AS component_path,
        CASE WHEN (DATE - NOW() < 30) THEN bug_id ELSE NULL END AS id1,
        CASE WHEN status_id = 'VERIFIED' THEN bug_id ELSE NULL END AS id2
    FROM buganizer.metadata.latest 
    -- need to add some join with "histories" table
    WHERE histories.component_path LIKE 'myTeam%' AND type_id = 'BUG'
) AS A
GROUP BY A.component_path

如何计算同一组的两个条件

1 个答案: