Question

我正在编写一个脚本来收集字段名称（dialogPartyASelection_ *＆amp;＆amp; dialogPartyBSelection_ *），然后比较这两个值以查看它们是否匹配。在比较之前，字段的完整列表（选择）被分解为“组”。我可以突破某些部分（IE，通过迭代比较两个字段值）并成功测试，但是当将所有内容整合在一起时，脚本似乎无法正确比较。我可能正在接近这个/设置自己做错了，（已经开始玩创建地图，以A方为键，以B方为价值）。

代码片段：

    // Test Variables
PartyBSelection_Propertieshamster = 'Accepted'
PartyBSelection_Propertieszembra = 'Agreed'
PartyBSelection_Propertiesdogs = 'Agreed'
PartyBSelection_Propertiescats  = 'Decision taken'
PartyASelection_Propertieshamster = 'Accepted'
PartyASelection_Propertieszembra = 'Agreed'
PartyASelection_Propertiesdogs = 'Agreed'
PartyASelection_Propertiescats = 'Decision taken'
// example of selections(there are lots of entries for A/B party) = ['dialogPartyBSelection_Communication','dialogPartyASelection_Housing','dialogPartyASelection_Income','PartyASelection_Properties']
def selectedGroup = { s -> selections.findAll { it.contains s}} // for pulling groups of questions from list
def isAgreed = { a, b -> (a in ['Agreed', 'Decision taken','Accepted'] && b in ['Agreed', 'Decision taken','Accepted']) } // for comparing values

for(questions in selectedGroup("Properties")){
   {k -> percentCompleteProperties += isAgreed("PartyASelection_${k}", "PartyBSelection_${k}")? 1 : 0}
   println questions
   println percentCompleteProperties
}

当前输出：

PartyBSelection_Propertiescats

0

PartyBSelection_Propertieshamster

0

PartyBSelection_Propertiesdogs

0

PartyBSelection_Propertieshamster

0

PartyASelection_Propertiescats

0

PartyASelection_Propertieshamster

0

PartyASelection_Propertiesdogs

0

PartyASelection_Propertieshamster

0

Answer 1

这是示例代码但我改变了测试数据等请检查此逻辑是否适合您的情况。

// Test Variables
def testVariables = [
    'PartyBSelection_PropertiesAssets':'Accepted',
    'PartyBSelection_PropertiesDebts': 'Agreed',
    'PartyBSelection_PropertiesMoney': 'Agreed',
    'PartyBSelection_PropertiesSpecialGoods':'Decision taken',
    'PartyASelection_PropertiesAssets':'Accepted',
    'PartyASelection_PropertiesDebts':'Agreed',
    'PartyASelection_PropertiesMoney':'Agreed',
    'PartyASelection_PropertiesSpecialGoods':'Decision taken'
]

List<String> selections= [
    'PropertiesAssets',
    'PropertiesDebts',
    'PropertiesMoney',
    'PropertiesSpecialGoods',
    'PropertiesAssets',
    'PropertiesDebts',
    'PropertiesMoney',
    'PropertiesSpecialGoods'
]


def selectedGroup = { s -> selections.findAll { it.contains s}}
List<String> okLabels = ['Agreed', 'Decision taken','Accepted']
def isAgreed = {a, b ->
    (testVariables[a] in okLabels && testVariables[b] in okLabels)
}

List<Map<String, Integer>> result = selectedGroup("Properties").collect {String question ->
    [(question) : isAgreed("PartyASelection_${question}", "PartyBSelection_${question}")? 1 : 0 ]
}

assert result == [
    ['PropertiesAssets':1],
    ['PropertiesDebts':1],
    ['PropertiesMoney':1],
    ['PropertiesSpecialGoods':1],
    ['PropertiesAssets':1],
    ['PropertiesDebts':1],
    ['PropertiesMoney':1],
    ['PropertiesSpecialGoods':1]
]

其他方式

def r = [:]
def questionsCount = selectedGroup("Properties").size()
selectedGroup("Properties").eachWithIndex {String question, Integer i ->
    println "question:${question}(${i+1}/${questionsCount})"
    r.put(question,isAgreed("PartyASelection_${question}", "PartyBSelection_${question}")? 1 : 0 )
}
// This version includes all records in to the one map.
// Also, a record that is duplicated (as key) is overwritten.
r == [PropertiesAssets:1, PropertiesDebts:1, PropertiesMoney:1, PropertiesSpecialGoods:1]

然后输出：

question:PropertiesAssets(1/8)
question:PropertiesDebts(2/8)
question:PropertiesMoney(3/8)
question:PropertiesSpecialGoods(4/8)
question:PropertiesAssets(5/8)
question:PropertiesDebts(6/8)
question:PropertiesMoney(7/8)
question:PropertiesSpecialGoods(8/8)

Groovy迭代列表变量

1 个答案: