我已经从JSON反序列化了一个对象:
dynamic bookdata = JsonConvert.DeserializeObject(bookdata_);
dynamic boy = orderbookdata.asks;
现在,动态boy
包含以下数据:
{[ [25,32], [33,44], [22,11], [57.98,2.22] ]}
我想将这些数据放入更有条理的格式,而不是将其保存在boy
中。例如。字典等...
json结构是这样的:
{
"name": "aal",
"symbol": "ltd",
"timestamp": 1464703002,
"asks": [
[25, 32],
[33, 44],
[22, 11],
[57.98, 2.22]
]
}
我想将[25, 32], [33, 44], [22, 11], [57.98, 2.22]
提取到每个单独的值中,然后弹出两列列表视图。
答案 0 :(得分:1)
如果dynamic
boy
包含以下数据{[ [ 25, 32 ], [ 33, 44 ], [ 22, 11 ], [ 57.98, 2.22 ]]}
,请参阅以下代码:
dynamic bookdata = JsonConvert.DeserializeObject(bookdata_);
dynamic boy = orderbookdata.asks;
double[][] e = ((IEnumerable<dynamic>)boy)
.Select(b => ((IEnumerable<dynamic>)b)
.Cast<double>()
.ToArray())
.ToArray();
如果需要Dictionary<first_value, second_value>
:
dynamic bookdata = JsonConvert.DeserializeObject(bookdata_);
dynamic boy = orderbookdata.asks;
Dictionary<double, double> d = ((IEnumerable<dynamic>)boy)
.Select(b => ((IEnumerable<dynamic>)b)
.Cast<double>())
.ToDictionary(i => i.First(), i => i.Last());