Question

String = "ask not what your country can do for you ask"
words = ["ask","not","what","your","country","can","do","for","you","ask"]
positions = [1,2,3,4,5,6,7,8,9,1]

for word in String():
   if not word in words:
      words.append(word)
   i = words.index(word)
   positions.append(i)

s = "" 
for i in positions:
   s = s + words[i] + " "

print(s)

当我在游戏场中编写此代码时，它会出现以下错误类型＆＃39;测试＆＃39;不符合协议＆＃39; AnyObject＆＃39;

我猜它失败了，因为struct是一个值类型而不是引用类型。但是当我运行这段代码时

 </div>
        <div class="modal-footer">
            <button type="button" class="btn btn-default" data-dismiss="modal" onclick="resetFunction();">Yes</button>
            <button type="button" class="btn btn-default"  onclick="reprintLabel();">No, Reprint Label</button>
        </div>
    </div>

有效但这些都是值类型，但在这种情况下没有给出错误为什么？

Answer 1

对于你的成功案例，幕后会有一些转换。

尝试在附加的末尾添加此内容，以查看发生了什么：

$sql = "SELECT id 
        FROM location
        WHERE id IN (?)";
$locations = $this->db->query($sql, $this->input->post('location'));

类型转换对于AnyObject来表示任何引用类型的实例

1 个答案: