Question

我有一个字符串如下

Esophageal have not 45.3
The end is nigh 23
Maybe (just) (maybe>32) 45.2

每一行都以数字结尾（包含小数点和不包含小数点）我想在最后一个数字

之前拆分该行

我试过这个正则表达式：

    myarray[]=null;
    myarray=match.split("/\\s+(?=\\S*+$)/");

但它没有拆分

Answer 1

您可以使用此

String Str = "Maybe (just) (maybe>32) 45.2"; 

for (String retval: Str.split("\\s(?=\\b(\\d+(?:\\.\\d+)?)$)")){
   System.out.println(retval);
}

<强> Ideone Demo

Answer 2

只需拆分字符串并获取数组的最后一个值：

    String[] array = "Maybe (just) (maybe>32) 45.2".split(" ");
    String firstPart = array[0];
    String lastPart = array[array.length-1];
    for (int i = 1; i < array.length - 1; i++) {
        firstPart += " " + array[i]; 
    }

    System.out.println(firstPart);
    System.out.println(lastPart);

Answer 3

match.split("[ \\t](?=[.\\d]+([\\n\\r]+|$))");

结果应该如下：

Esophageal have not
45.3 The end is nigh
23 Maybe (just) (maybe>32)
45.2

按最后一个空格拆分，包括java中的标签空间

3 个答案: