Question

如果我有一个Groovy嵌套列表，例如： List list = ['a', 'b', 'c', ['d', 'e', ['f']]]

我希望能够在列表中搜索特定元素，比如'd'，然后将该元素转换为其他内容，例如['g'，'h']，以便新列表如下所示： ['a', 'b', 'c', [['g', 'h'], 'e', ['f']]]

Answer 1

喜欢这个??

List list = ['a', 'b', 'c', ['d', 'e', ['f']]]
assert list.collectNested{
    if (it == 'd') {
        ['g', 'h']
    } else {
        it
    }
} == ['a', 'b', 'c', [['g', 'h'], 'e', ['f']]]

Answer 2

使用以下通用方法： -

def findAndReplace(def listValue, def listIndex, def valueToCompare, def valueToReplace, def originalList) {
    if(listValue instanceof List) {
        listValue.eachWithIndex { insideListValue, insideListIndex ->
                findAndReplace(insideListValue, insideListIndex, valueToCompare, valueToReplace, listValue)
      }
   }else if(listValue == valueToCompare) {
            originalList[listIndex] = valueToReplace
   }
}

List originalList = ['a', 'b', 'c', ['d', 'e', ['f']]]
def valueToCompare = 'd'
def valueToReplace =  ['g', 'h']
originalList.eachWithIndex { listValue, listIndex ->
    findAndReplace(listValue, listIndex, valueToCompare, valueToReplace, originalList)
}
println originalList

输出：[a, b, c, [[g, h], e, [f]]]

希望它会帮助你...... :)

在嵌套列表中查找元素并进行转换（groovy）

2 个答案: