Question

我跟随json：

[
   {"data"=>"data1", "value1"=>10, "value2"=>6, "day"=>"05-20-2016"},
   {"data"=>"data1", "value1"=>17, "value2"=>10, "day"=>"05-21-2016"},
   {"data"=>"data1", "value1"=>12, "value2"=>8, "day"=>"05-22-2016"},
   {"data"=>"data2", "value1"=>5, "value2"=>1, "day"=>"05-20-2016"},
   {"data"=>"data2", "value1"=>11, "value2"=>3, "day"=>"05-21-2016"},
   {"data"=>"data2", "value1"=>25, "value2"=>18, "day"=>"05-22-2016"}
]

我想要的是在带有C3.js的折线图中显示这些值，并为每个值分别显示一行。

基于这个例子，我希望有一行用于data1和value1，一行用于data1和value2，一行用于data2和value1，一行用于data2和value2，在图例中我想要有Value1＆gt; Data1，Data2（每个数据行都有不同的颜色）。

现在，当我在C3.js中加载它时，它只显示2行（一行用于data1，一行用于data2）。

有人能告诉我到底该怎么做吗？

Answer 1

这是一个数据争论练习，你想要转换像

这样的数据

{"data"=>"data1", "value1"=>10, "value2"=>6, "day"=>"05-20-2016"},
...
{"data"=>"data2", "value1"=>5, "value2"=>1, "day"=>"05-20-2016"},

类似

{"data1value1"=>10, "data1value2"=>6,
 "data2value1"=>17, "data2value2"=>10, "key"=>"05-20-2016"},

这可以这样实现：

var json = [
   {"data":"data1", "value1":10, "value2":6, "day":"05-20-2016"},
   {"data":"data1", "value1":17, "value2":10, "day":"05-21-2016"},
   {"data":"data1", "value1":12, "value2":8, "day":"05-22-2016"},
   {"data":"data2", "value1":5, "value2":1, "day":"05-20-2016"},
   {"data":"data2", "value1":11, "value2":3, "day":"05-21-2016"},
   {"data":"data2", "value1":25, "value2":18, "day":"05-22-2016"}
];


var valFields = ["value1", "value2"];
var dataIndexField = "data";
var keyField = "day";
var newMap = {}; // new data will be built up in here
json.forEach (function (d) {
    // get new data obj for key, which in this case is the day value
    var key = d[keyField];
    var newObj = newMap[key];
    if (!newObj) { // make the obj if it doesn't exist
        newObj =  {key: key};
        newMap[key] = newObj;
    }

    // in this obj merge the dataIndexField and valFields to make new datapoints
    var dataIndex = d[dataIndexField]; // either data1 or data2
    valFields.forEach (function (vField) { // vfield will loop value1 then value2
        newObj[dataIndex+vField] = d[vField]; // data1/2value1/2 = the value of value1/2
    });
});
var newJson = d3.values(newMap); // array of objs suitable for c3
// dataFields are the names of the new datapoint properties minus 'key'
var newDataFields = d3.keys(newJson[0]);
newDataFields.splice (newDataFields.indexOf("key"), 1); 



var chart = c3.generate({
    data: {
        json: newJson,
        keys: {
            x: 'key',
            value: newDataFields
        }
    },
  axis: {
    x: {
       type: 'category'
    }
  }
});

http://jsfiddle.net/w7o8k40q/3/

基本上，中间的位合并了data1 / 2和value1 / 2数字，就像你问的那样，并将它们添加到具有唯一键的对象中，在这种情况下取自每行的day字段。 newJson的Json.stringified输出如下：

[
    {"key":"05-20-2016","data1value1":10,"data1value2":6,"data2value1":5,"data2value2":1},
    {"key":"05-21-2016","data1value1":17,"data1value2":10,"data2value1":11,"data2value2":3},
    {"key":"05-22-2016","data1value1":12,"data1value2":8,"data2value1":25,"data2value2":18}
]

如果你告诉它每行中哪些属性是数据（这是newDataFields做什么）以及哪一个是x值的关键（PS，因为我们将关键字解释为分类值），这对c3来说已经足够了你可能需要通过关键字段对json进行排序，这样日子就不会出现反过来了 - 幸运的是我们在原始数据集中按顺序遇到它们了）

在C3.js折线图中显示多个数据集

1 个答案: