Question

我有一个如下所示的字符串

var indicator = -65(www.anyweb.com)

数字-65也可以是任何数字。如何在javascript中单独取出网址？

Answer 1

您需要在'（'和之前'）'

之后提取字符串

var str = "-65(www.anyweb.com)";
str = str.substring(str.lastIndexOf("(")+1,str.lastIndexOf(")"));

Answer 2

You can use this example for string operations




var data = "-65(www.anyweb.com)";
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));    console.log("URL :: ",url);

Answer 3

＆＃13;

var domain = /\((.*?)\)/.exec("-65(www.anyweb.com)")[1];
console.log(domain);

＆＃13;

上面的正则表达式将创建一个包含括号内任何内容的组。

Answer 4

您可以使用一些简单的字符串操作：

var str = "-65(www.anyweb.com)";
var url = "N/A";

// Find indices of open and close parentheses
var open  = str.indexOf("(");
var close = str.lastIndexOf(")");

// If they were found then extract the URL from the string
if (open !== -1 && close !== -1) {
    url = str.substring(open + 1, close);
}
console.log(url);

如果您更倾向于使用正则表达式，那么应该这样做：

var str = "-65(www.anyweb.com)";
var regex = /\((.*?)\)/; // Capture URL inside parentheses
var result = regex.exec(str); // Execute the regex against the string
var url = "N/A";

// If the URL was matched then assign it to the variable
if (result[1] !== undefined) {
  url = result[1];
}
console.log(url);

您也可以简单地替换您不想要的东西：

var str = "-65(www.anyweb.com)";
str = str.replace(/^.*\(/, ""); // Remove everything before URL
str = str.replace(/\).*$/, "");  // Remove everything after URL
console.log(str);

Answer 5

Example 1 : 
var data = "-65(www.anyweb.com)";

if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
} 
console.log("URL :: ",url);

Example 2 : 
var data = "-65";

if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
} 
console.log("URL :: ",url);

Example 3 : 
var data = "-65(www.anyweb.com)6764872";

if(data.indexOf('(')!=-1){
var url = data.slice(data.indexOf('(')+1 ,data.indexOf(')'));
} 
console.log("URL :: ",url);

在javascript中剪切字符串URL

5 个答案: