我正在努力将JSONEditor集成到Django管理员中。我的模型中有一个字段使用Postgres JSON,这个库中的树编辑器是完美的。
class Executable(models.Model):
""" Simplified model for sake of the question."""
recipe = JSONField(null=True, blank=True)
我已经取得了不错的进展(我认为)将JSONEditor库集成到Django Admin的相应创建/编辑屏幕中。加载时数据正确显示但由于某些原因,当我在JSONEditorWidget中进行编辑时,不会保存更改。我确定有一些save
覆盖我需要处理,或者我错过了一些明显的东西,但我真的不知道从哪里开始。
import json
from django import forms, utils
from django.contrib import admin
from .models import Executable
class JSONEditorWidget(forms.Widget):
html_template = """
<div id='%(name)s_editor_holder'></div>
<script type="text/javascript">
var options = {
"mode": "tree",
"search": true
};
var %(name)s_editor = new JSONEditor(container, options);
var json = %(value)s
%(name)s_editor.set(json);
%(name)s_editor.expandAll();
var json = %(name)s_editor.get(json);
</script>
<textarea readonly class="vLargeTextField" cols="40" id="id_%(name)s" name="%(name)s" rows="2" height="20px">%(value)s</textarea>
"""
def __init__(self, attrs=None, formats=None, defaults=None):
self.formats = formats
self.defaults = defaults
super(JSONEditorWidget, self).__init__(attrs)
def render(self, name, value, attrs=None):
if isinstance(value, basestring): # Edit existing instance
value = json.loads(value)
result = self.html_template % {
'name': name,
'value': json.dumps(value)
}
return utils.safestring.mark_safe(result)
class ExecutableForm(forms.ModelForm):
recipe = forms.CharField(widget=JSONEditorWidget()) # Kwargs here?
class Meta:
model = Executable
fields = '__all__'
class Media:
css = {
'all': ('http://www.jsoneditoronline.org/app.min.css',) # TEMP
}
js = (
'http://www.jsoneditoronline.org/app.min.js', # TEMP
)
class ExecutableAdmin(admin.ModelAdmin):
model = Executable
form = ExecutableForm
fields = (('request', 'status'), 'recipe')
admin.site.register(Executable, ExecutableAdmin)
答案 0 :(得分:12)
我的Django 1.10.2解决方案,jsoneditor#^ 5.5.9,Postgres 9.5:
<强> models.py 强>
from django.contrib.postgres.fields import JSONField
class Consumer(models.Model):
data = JSONField(default=dict, db_index=True)
<强> admin.py:强>
from django import forms
from django.contrib import admin
from django.utils.safestring import mark_safe
from django.template.loader import render_to_string
from .models import Consumer
class JSONEditorWidget(forms.Widget):
template_name = 'jsoneditor.html'
def render(self, name, value, attrs=None):
context = {
'data': value,
'name': name
}
return mark_safe(render_to_string(self.template_name, context))
class ConsumerForm(forms.ModelForm):
class Meta:
model = Consumer
fields = '__all__'
widgets = {
'data': JSONEditorWidget()
}
class Media:
css = { 'all': ('jsoneditor/dist/jsoneditor.min.css',) }
js = ('jsoneditor/dist/jsoneditor.min.js', )
class ConsumerAdmin(admin.ModelAdmin):
list_display = ['pk']
model = Consumer
form = ConsumerForm
admin.site.register(Consumer, ConsumerAdmin)
<强> jsoneditor.html:强>
<div id="{{ name }}_editor"></div>
<textarea cols="40" id="id_{{ name }}" name="{{ name }}" rows="10" required="" style="display: none">{{ data }}</textarea>
<script>
console.log('jsoneditor.html');
var container = document.getElementById("{{ name }}_editor");
var options = {
modes: ['code', 'tree'],
search: true,
onChange: function () {
var json = editor.get();
document.getElementById("id_{{ name }}").value=JSON.stringify(json);
}
};
var editor = new JSONEditor(container, options);
var json = {{ data|safe }};
editor.set(json);
</script>
块引用 用StackEdit撰写。