正则表达式用“和”替换相同的单词

Question

在下面的例句中：

  

绿色衬衫绿帽

是否可以使用正则表达式检测2个相同的单词并将第二个单词替换为and以成为：

  

绿色衬衫和帽子

一个更难的字符串示例。这里需要替换第一个相同的单词：

  

你是一位具有艺术天赋的音乐天才

应该成为：

  

你是一位具有艺术天赋和音乐天赋的人

Answer 1

描述

首先，正则表达式不是最理想的解决方案，但我相信你有理由使用它。

\1and\4

替换为： and

摘要

此正则表达式将在字符串中找到两个相同的单词，并将第二个单词替换为Green shirt green hat Green shirt greenish hat You are an artistically gifted musically gifted individual 。

实施例

现场演示

GRPC

示例文字

Green shirt and hat
Green shirt greenish hat
You are an artistically gifted musically and individual

样本匹配

NODE                     EXPLANATION
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    (                        group and capture to \2:
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
      [a-z]{1,}                any character of: 'a' to 'z' (at least
                               1 times (matching the most amount
                               possible))
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
    )                        end of \2
----------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (                        group and capture to \3:
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
    \2                       what was matched by capture \2
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
  )                        end of \3
----------------------------------------------------------------------
  (                        group and capture to \4:
----------------------------------------------------------------------
    .*                       any character except \n (0 or more times
                             (matching the most amount possible))
----------------------------------------------------------------------
  )                        end of \4
----------------------------------------------------------------------
  $                        before an optional \n, and the end of a
                           "line"
----------------------------------------------------------------------

解释

a-z

额外信用

虽然OP中没有解决，但如果相关字词使用非[a-z]个字符，那么您可以将[a-z]|[^\x00-\x7F]替换为与\b\2\b匹配的非英文字符。但是，我们需要将(?<=\s|^)\2(?=\s|$)更改为((\b(?:[a-z]|[^\x00-\x7F]){1,}\b).*?)((?<=\s|^)\2(?=\s|$))(.*)$ ，以便我们确保正确匹配。

mocha mytest.js --require myglobals.js

现场演示 https://regex101.com/r/yG3yM6/2

Answer 2

通过修改this answer，您可以执行此操作：

＆＃13;

＆＃13;

console.log( myFunc("Green shirt green hat") );
console.log( myFunc("Big red eyed rabbits red Ferrari") );

function myFunc(str) {
    return str.replace(/\b(\w+)(.+)(\1)\b/gi, "$1$2and");
}

＆＃13;

＆＃13;

＆＃13;

Answer 3

您可以使用RegExp /(\bgreen\b)/ig，其中green是要匹配的字词，String.prototype.replace()，在替换函数中达到p2时

  

p1，p2，...第n个带括号的子匹配字符串，前提是   replace（）的第一个参数是RegExp对象。 （对应于   上面有$1，$2等。）例如，如果给出了/(\a+)(\b+)/，   p1匹配\a+，p2匹配\b+。

将green替换为and

＆＃13;

＆＃13;

var str = "Green shirt green hat green";
var re = function(m, p1, p2, index) {
  return p2 ? "and" : m
}
str = str.replace(/(\bgreen\b)/ig, re);
console.log(str);

＆＃13;

＆＃13;

＆＃13;

Answer 4

您可以使用以下内容：

/(\b([^\s]+)\b.*?)\b\2\b/gi

测试用例：

var regex = /(\b([^\s]+)\b.*?)\b\2\b/gi;
'Green shirt green hat with blue shoes blue glasses'.replace(regex, '$1and')
  === 'Green shirt and hat with blue shoes and glasses';
'Orange colored oranges orange belts'.replace(regex, '$1and')
  === 'Orange colored oranges and belts';

Try it online

Answer 5

您的第一个示例的答案 - 我将其视为用＆＃39;＆＃39; 替换第一个重复单词的第二个 - 是：

＆＃13;

＆＃13;

var str = 'Green shirt green hat';

str = str.replace(/(\b\S+\b)(.+?)(\b\1\b)/i, '$1$2and');

console.log(str);

＆＃13;

＆＃13;

＆＃13;

你的第二个例子 - 我读作用＆＃39;＆＃39; 替换第一个重复的单词 - 的答案是：

＆＃13;

＆＃13;

var str = 'You are an artistically gifted musically gifted individual';

str = str.replace(/(\b\S+\b)(.+?)(\b\1\b)/i, 'and$2$1');

console.log(str);

＆＃13;

＆＃13;

＆＃13;