Question

我正在尝试实现一个功能，要求几个q存储它们返回有趣的句子与这些输入。但它没有工作，没有显示错误，但是列表没有保存用户自己的3个输入，并注意到每次它将输入保存在alist数组中..取代了之前的列表项，但是我想保存所有这三个。

for(i = 0; i < 3; i++) {
        var qlist = ["adjective?","Verb?", "noun?"];
        var alist = [];
        alist[i] = prompt(qlist[i] + "[questions number-" + i + "]");
    }
    var statement = document.write("There once was a "+ alist[0] + " programmer who once wanted to use javascript to " + alist[1] + " the " + alist[2]);    
    alert(statement);

Answer 1

alist需要在循环之外初始化。否则你会覆盖它。

另外，不要警告（声明）这种类型是未定义的。

另外，不要初始化qlist 3次。

let alist = [];
let qlist = ["adjective?","Verb?", "noun?"];
for(let i = 0; i < 3; i++) {
    alist[i] = prompt(qlist[i] + "[questions number-" + i + "]");
}
let statement = document.write("There once was a "+ alist[0] + " programmer who once wanted to use javascript to " + alist[1] + " the " + alist[2]);

Answer 2

你的alist是在for循环中定义的，你需要把它放在外面：

var qlist = ["adjective?","Verb?", "noun?"];
var alist = [];
for(i = 0; i < 3; i++) {
    alist[i] = prompt(qlist[i] + "[questions number-" + i + "]");
}
var statement = document.write("There once was a "+ alist[0] + " programmer who once wanted to use javascript to " + alist[1] + " the " + alist[2]);    
alert(statement);

用Js实现有趣的游戏

2 个答案: