Question

我有以下代码我想检测一下手机的屏幕但函数onReceive永远不会被调用有谁能给我一个解决方案。请帮忙。如果有人有任何其他工作代码，请帮助。谢谢

package com.pack;

import android.app.Activity;
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.os.Bundle;

public class Screen extends Activity {

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        IntentFilter filter = new IntentFilter();
        filter.addAction(Intent.ACTION_SCREEN_OFF);
     Context con = this;
        this.registerReceiver(new BroadcastReceiver() {

              @Override
              public void onReceive(Context context, Intent intent) {
               System.out.println("Screen off...................");
              }
            }, new IntentFilter(Intent.ACTION_SCREEN_OFF));
    }

}

Answer 1

您的代码适合我。我修改了代码，因此它更容易阅读并添加了一些sysout，但它的工作方式与你的编写方式相同：

public class Test extends Activity {

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_OFF);
    registerReceiver(new BroadcastReceiver() {

        @Override
        public void onReceive(Context context, Intent intent) {
            System.out.println("Screen off...................");
        }

    }, filter);
}

@Override
protected void onResume() {
    super.onResume();
    System.out.println("onResume()");
}

@Override
protected void onDestroy() {
    super.onDestroy();
    System.out.println("onDestroy()");
}

@Override
protected void onPause() {
    super.onPause();
    System.out.println("onPause()");
}

如果我这样做，它会打印以下内容（开始活动，关闭屏幕，打开屏幕，按后退按钮）：

onResume()
onPause()
Screen off...................
onResume()
onPause()
onDestroy()

此后活动被销毁，因此不会显示任何事件。也许你想在AndroidManifest中注册你的BroadcastReceiver。

onReceive从未打过电话

1 个答案: