Question

我从类似于以下结构的视图中获取数据

Column A        Column B    Column C    Column D    Column E
Platform Total  Plant A     Product A   Date        NULL
Platform 1      Plant A     Product A   Date        100
Platform 2      Plant A     Product A   Date        200
Platform Total  Plant B     Product B   Date        NULL
Platform 5      Plant B     Product B   Date        150
Platform 6      Plant B     Product B   Date        250

如何以下列格式获取数据

Column A        Column B    Column C    Column D    Column E
Platform Total  Plant A     Product A   Date        300
Platform 1      Plant A     Product A   Date        100
Platform 2      Plant A     Product A   Date        200
Platform Total  Plant B     Product B   Date        400
Platform 5      Plant B     Product B   Date        150
Platform 6      Plant B     Product B   Date        250

即，E列应为E列中的值的总和，其中A列='平台总数'，B列和C列具有相同的值。尝试自我加入，但无法弄明白。

感谢您抽出宝贵时间回答这个问题。

Answer 1

您可以使用窗口函数和条件参数：

select t.*,
       coalesce(t.e,
                sum(e) over (partition by t.b, t.c)
               ) as e
from t;

实际上，这只是查找null值。您希望将其设置为a中的特定值：

select t.a, t.b, t.c, t.d,
       (case when t.a = 'Platform Total'
             then sum(t.e) over (partition by t.b, t.c)
             else t.e
        end) as e
from t;

Answer 2

只需使用UNION

即可

SELECT A,B,C,D FROM Table1
UNION
SELECT 'Total',SUM(B),SUM(C),SUM(D) FROM Table2

Answer 3

select ColumnA, ColumnB, ColumnC, ColumnD, Column E 
from table 
where ColumnA <> 'Platform Total' 
union all 
select 'Platform Total', ColumnB, ColumnC, max(ColumnD), sum(Column E) 
from table 
where ColumnA <> 'Platform Total'  
group by ColumnB, ColumnC

获取单行SQL中的行总和

3 个答案: