Question

使用sed给出以下结果：

~ echo drive kids to the Foo Bar +09:00-10:00 | sed 's/\ *+[a-zA-Z0-9\{._\-\:\-}]*\ */ /g'
drive kids to the Foo Bar -10:00
~ echo drive kids to the Foo Bar +09:00-10:00 | sed 's/\ *+[a-zA-Z0-9\{._\-\}]*\ */ /g'
drive kids to the Foo Bar :00-10:00
~ echo pick suzieq up from +10:30-11:00 kung foobar practice | sed 's/\ *+[a-zA-Z0-9\{._\-\}]*\ */ /g'
pick suzieq up from :30-11:00 kung foobar practice
~ echo +11:15-12 pick kids and new friends up from Foo Bar | sed 's/\ *+[a-zA-Z0-9\{._\-\}]*\ */ /g'
 :15-12 pick kids and new friends up from Foo Bar

我想要的是：

~ echo drive kids to the Foo Bar +09:00-10:00 | sed 'some regular expression'
drive kids to the Foo Bar 
~ echo drive kids to the Foo Bar +09:00-10:00 | sed 'some regular expression'
drive kids to the Foo Bar 
~ echo pick suzieq up from +10:30-11:00 kung foobar practice | sed 'some regular expression'
pick suzieq up from kung foobar practice
~ echo +11:15-12 pick kids and new friends up from Foo Bar | sed 'some regular expression'
 pick kids and new friends up from Foo Bar

作为旁注：我有a regular expression可以在+符号后选择我想要的所有内容，但是我如何将我在rubular中所做的内容翻译为sed，以便sed将：“选择除正则表达式之外的所有内容”？谢谢你的帮助：）

编辑：

~/sandbox/sed-practice echo drive kids to the Foo Bar +09:00-10:00 | sed 's/([+][^[:space:]]+)?./\1/g'
sed: 1: "s/([+][^[:space:]]+)?./ ...": \1 not defined in the RE

~/sandbox/sed-practice echo drive kids to the Foo Bar +09:00-10:00 | sed -r 's/([+][^[:space:]]+)?./\1/g'
sed: illegal option -- r
usage: sed script [-Ealn] [-i extension] [file ...]
       sed [-Ealn] [-i extension] [-e script] ... [-f script_file] ... [file ...]

Answer 1

用！

扭转限制

有时您需要在除了与正则表达式匹配的行之外的每一行上执行操作，或者在一系列地址之外执行操作。＆＃34;！＆＃34;字符，通常意味着不在UNIX实用程序中，反转地址限制。你记得那个

sed -n '/match/ p'

就像grep命令一样。＆＃34; -v＆＃34; grep选项打印所有不包含该模式的行。 Sed可以用

做到这一点

sed -n '/match/ !p'

找到答案here

Answer 2

您可以使用此sed命令：

# original input
cat file
drive kids to the Foo Bar +09:00-10:00
pick suzieq up from +10:30-11:00 kung foobar practice
+11:15-12 pick kids and new friends up from Foo Bar

# sed command
sed 's/\(.*\)+[^[:space:]]*[[:blank:]]*/\1/g' file

drive kids to the Foo Bar
pick suzieq up from kung foobar practice
pick kids and new friends up from Foo Bar

[[:blank:]]匹配空格或标签
[[:space:]]匹配空格或制表符或换行符

如何匹配除sed的正则表达式之外的所有内容？

2 个答案:

用！