我正在尝试将JSONObject转换为JSONArray，但存在一些问题。我的代码是：
public ArrayList<Users> parseJSON(String result) {
ArrayList<Users> users = new ArrayList<Users>();
try {
JSONArray jArray = new JSONArray(result);
for (int i = 0; i < jArray.length(); i++) {
JSONObject json_data = jArray.getJSONObject(i);
Users user = new Users();
user.setId(json_data.getInt("cus_id"));
user.setName(json_data.getString("cus_Name"));
user.setPlace(json_data.getString("cus_city"));
users.add(user);
}
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data " + e.toString());
}
return users;
}
logcat的：
05-30 17:30:16.152 5956-5956/com.example.vari.table_format E/log_tag:
Error parsing data org.json.JSONException: Value
{"Customer_mas":[{"Id":8,"cus_id":"CUS0001","cus_Name":"SUNRISE ELECTRONICS","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 7:20AM","Updated_date":"Nov 20 2013 7:20AM"},{"Id":9,"cus_id":"CUS0002","cus_Name":"LGB VAYAMPALAYAM","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 7:56AM","Updated_date":"Nov 20 2013 7:56AM"},{"Id":10,"cus_id":"CUS0003","cus_Name":"LGB ANNUR","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 7:56AM","Updated_date":"Nov 20 2013 7:56AM"},{"Id":31,"cus_id":"CUS0024","cus_Name":"INTELLE ENGG","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 8:07AM","Updated_date":"Nov 20 2013 8:07AM"},{"Id":32,"cus_id":"CUS0025","cus_Name":"JAAZ ELECTRO","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 8:07AM","Updated_date":"Nov 20 2013 8:07AM"},{"Id":33,"cus_id":"CUS0026","cus_Name":"JEEVAN ELECTRONICS","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 8:07AM","Updated_date":"Nov 20 2013 8:07AM"},{"Id":34,"cus_id":"CUS0027","cus_Name":"J.K.R ENGINERS","cus_city":"COIMBATORE","Created_date":"Nov 20 2013 8:07AM","Updated_date":"Nov 20 2013 8:07AM"}]} of type org.json.JSONObject cannot be converted to JSONArray
JSON回复：
{
"Customer_mas":[
{
"Id":8,
"cus_id":"CUS0001",
"cus_Name":"SUNRISE ELECTRONICS",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 7:20AM",
"Updated_date":"Nov 20 2013 7:20AM"
},
{
"Id":9,
"cus_id":"CUS0002",
"cus_Name":"LGB VAYAMPALAYAM",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 7:56AM",
"Updated_date":"Nov 20 2013 7:56AM"
},
{
"Id":10,
"cus_id":"CUS0003",
"cus_Name":"LGB ANNUR",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 7:56AM",
"Updated_date":"Nov 20 2013 7:56AM"
},
{
"Id":31,
"cus_id":"CUS0024",
"cus_Name":"INTELLE ENGG",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 8:07AM",
"Updated_date":"Nov 20 2013 8:07AM"
},
{
"Id":32,
"cus_id":"CUS0025",
"cus_Name":"JAAZ ELECTRO",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 8:07AM",
"Updated_date":"Nov 20 2013 8:07AM"
},
{
"Id":33,
"cus_id":"CUS0026",
"cus_Name":"JEEVAN ELECTRONICS",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 8:07AM",
"Updated_date":"Nov 20 2013 8:07AM"
},
{
"Id":34,
"cus_id":"CUS0027",
"cus_Name":"J.K.R ENGINERS",
"cus_city":"COIMBATORE",
"Created_date":"Nov 20 2013 8:07AM",
"Updated_date":"Nov 20 2013 8:07AM"
}
]
}
答案 0 :(得分：1)
试试这个：
JSONObject obj = new JSONObject(result);
JSONArray jArray = obj.getJSONArray("Customer_mas");
for (int i = 0; i < jArray.length(); i++) {
JSONObject json_data = jArray.getJSONObject(i);
Users user = new Users();
user.setId(json_data.getString("cus_id"));
user.setName(json_data.getString("cus_Name"));
user.setPlace(json_data.getString("cus_city"));
users.add(user);
答案 1 :(得分：1)
像这样分析您的数据。
public ArrayList<Users> parseJSON(String result) {
ArrayList<Users> userList = new ArrayList<>();
try {
JSONObject jsonObject = new JSONObject(result);
JSONArray jsonArray = jsonObject.getJSONArray("Customer_mas");
for(int i =0; i<jsonArray.length();i++){
JSONObject jsonData = jsonArray.getJSONObject(i);
Users user = new Users();
user.setId(jsonData.getInt("id"));
user.setCus_id(jsonData.getString("cus_id"));
user.setName(jsonData.getString("cus_Name"));
user.setPlace(jsonData.getString("cus_city"));
userList.add(user);
}
} catch (JSONException e) {
e.printStackTrace();
}
return userList;
}
如果id的POJO对象类型是字符串，那么它肯定会起作用。
将此代码粘贴到Users.java类
中public class Users {
String cus_id;
String name;
String place;
int id;
public Users() {
this.cus_id = "";
this.name = "";
this.place = "";
this.id = 0;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getCus_id() {
return cus_id;
}
public void setCus_id(String cus_id) {
this.cus_id = cus_id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPlace() {
return place;
}
public void setPlace(String place) {
this.place = place;
}
}
答案 2 :(得分：0)
public void addData(ArrayList<Users> users) {
addHeader();
for (Iterator i = users.iterator(); i.hasNext();) {
Users p = (Users) i.next();
/** Create a TableRow dynamically **/
tr = new TableRow(this);
/** Creating a TextView to add to the row **/
label = new TextView(this);
label.setText(p.getName());
label.setId(p.getCus_id()); //here is the problem
label.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT,
LayoutParams.WRAP_CONTENT));
label.setPadding(5, 5, 5, 5);
label.setBackgroundColor(Color.GRAY);
LinearLayout Ll = new LinearLayout(this);
LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT,
LayoutParams.WRAP_CONTENT);
params.setMargins(5, 2, 2, 2);
//Ll.setPadding(10, 5, 5, 5);
Ll.addView(label,params);
tr.addView((View)Ll); // Adding textView to tablerow.
/** Creating Qty Button **/
TextView place = new TextView(this);
place.setText(p.getPlace());
place.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT,
LayoutParams.WRAP_CONTENT));
place.setPadding(5, 5, 5, 5);
place.setBackgroundColor(Color.GRAY);
Ll = new LinearLayout(this);
params = new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT,
LayoutParams.WRAP_CONTENT);
params.setMargins(0, 2, 2, 2);
//Ll.setPadding(10, 5, 5, 5);
Ll.addView(place,params);
tr.addView((View)Ll); // Adding textview to tablerow.
// Add the TableRow to the TableLayout
tl.addView(tr, new TableLayout.LayoutParams(
LayoutParams.MATCH_PARENT,
LayoutParams.WRAP_CONTENT));
}
}
label.setId（p.getCus_id（））; //这是问题