答案 0 :(得分:0)
试试这个
class ViewController: UIViewController ,NSLayoutManagerDelegate{
@IBOutlet weak var textView: UITextView!
var range :NSRange!
override func viewDidLoad() {
super.viewDidLoad()
textView.textContainer.layoutManager?.delegate = self
let str = textView.text as NSString
//Regardless of the repeated string
range = str.rangeOfString("cillium adipisicing")
print(range)
}
// Invoked while determining the soft line break point. When NO, NSLayoutManager tries to find the next line break opportunity before charIndex
func layoutManager(layoutManager: NSLayoutManager, shouldBreakLineByWordBeforeCharacterAtIndex charIndex: Int) -> Bool{
// charIndex is in the string or not
if range.location != NSNotFound && NSLocationInRange(charIndex, NSRange(location: range.location + 1, length: range.length - 1 )) {
print("range of string is truncated -> charIndex is \(charIndex)")
}
return true
}
}
但如果没有“”且截断的字词BreakLineByWord
charIndex is 0
希望它有所帮助:)