Question

我已设置会话，我希望使用ajax和jquery将数据登录autho控制器发送到配置文件控制器

    public function login_autho() {
            $this->load->library('session');
            $data = array(
                'uname' => $this->input->post('uname'),
                'upassword' => $this->input->post('upassword')
            );
            //fetch database usename and password
            $result = $this->login_model->login_user($data);

            //user name put in the session
            $data_session_set = array('logged' => 1, 'uname' => $this->input->post('uname'));
            $data = $this->session->set_userdata($data_session_set);

            print_r($result);
        }

        public function profile() {
            $this->load->view('header');
            //How to send user name from here  to success view page  and fetch  all data
            $this->load->view('user/success');

        }

这是我登录表单中的ajax脚本，用于检查用户名并传递然后登录

   <script>
    $('#login_form').submit(function (e)
    {
        e.preventDefault();
        var uname = $('#uname').val();
        var upassword = $('#upassword').val();
        if (uname == "" || upassword == "")
        {
            $('#error').show().html('All Fields are required');
        } else {
            $('#error').html("").hide();
            $.ajax({
                type: "POST",
                url: "<?= base_url(); ?>User_controller/login_autho/",
                data: {uname: uname, upassword: upassword},
                success: function (data) {
                    //if session is set then redirect to User_controller/profile but session can send data
                    if (data == '1')
                    {
                        window.location.replace("<?= base_url(); ?>User_controller/profile");

                    } else
                    {
                        alert('invalid');
                    }
                }
            });
            return false;
        }
    });
</script>

Answer 1

您可以通过编写

简单地在codeigniter中获取会话数据

$username = $this->session->userdata('uname');//uname is the session variable name.

您可以像这样从ajax向其他控制器发送数据。

<input hidden name="uname" value="<?php echo $username ?>" id="uname">

function(){
  var uname = $("#uname").val(); 
  $.ajax({
    url: "" ,
    type : "POST", 
    data:{username:uname},

  }).done(function(data){

  }).fail(function(data){
     console.log("hello fail");

  });//end fail
}

您也可以像这样发送其他数据字段。希望这会帮助你。

Answer 2

在控制器

中更改此内容

$data_session_set = array(
   'uname'  => $this->input->post('uname'),
   'logged_in' => TRUE # add this insted of 'logged' => 1
);

$this->session->set_userdata($data_session_set);

我建议您使用logged_in代替logged

在您的视图中添加

echo $this->session->userdata('uname');

或尝试

print_r($this->session->userdata('uname'));

参考文献

Retrieving Session Data - codeigniter.com

Codeigniter如何在视图中获取会话数据

2 个答案: