Question

表：员工

EmpID: INTEGER NOT NULL
DeptID: INTEGER NOT NULL
Name: Char(40) NOT NULL
Age: INTEGER NOT NULL
Salary: INTEGER NOT NULL

表：部门

DeptID: INTEGER NOT NULL
Name: CHAR(20) NOT NULL

我们需要编写一个SQL查询，输出所有部门的名称，使部门的平均工资大于10,00,000。输出应只包含一列：DeptName。

试过这个：

SELECT AVG(Salary) AS avg_salary ,DeptID FROM ( SELECT DeptID, Salary FROM employee GROUP BY 1) DeptID GROUP BY DeptID HAVING avg_salary > 10;

结果：无法加入。

Answer 1

以下是查询：

SELECT 
Department.name AS DeptName
FROM Department 
INNER JOIN Employee ON Department.DeptID = Employee.DeptID
GROUP BY Department.DeptID
HAVING AVG(Employee.Salary) > 1000000;

sql query group by departname with other table in other table

1 个答案: