Question

我有一个返回一些行的表，我们正在查看的是仅当rxID匹配时，以及那些amountPaid是否相反。

在屏幕截图中，我们有两个rxID为3350593的条目，其支付金额为2.35和-2.35。这是一种货币类型。

到目前为止，我的查询只返回那两行，因为它匹配rxId。 y.amountpaid在底部，无法找到，并且t.amountpaid不能仅在被t.rxid分组时被选中。

如果我可以获取查询以删除具有相同rxID和反向数量的paids的那两行，我将非常感激。

 SELECT x.*
  FROM 
(
 SELECT IsInstyRxFlag,   pri.payerReceiptItemId,   CONVERT(varchar,rx.oeDate, 101) rxOeDate,  CONVERT(DECIMAL(6,2), drx.payerOblig) payerObligation,    CONVERT(DECIMAL(6,2), pri.amountPaid) amountPaid,  pri.rxId,    CONVERT(DECIMAL(6,2), (pri.amountPaid - drx.payerOblig)) difference, rxeventid  
 FROM PayerReceiptItem pri 
 JOIN Rx ON rx.rxId = pri.rxId 
  JOIN DispenseRx drx ON rx.rxId = drx.rxId  
  WHERE CONVERT(DECIMAL(6,2), drx.payerOblig) <>  CONVERT(DECIMAL(6,2), pri.amountPaid)      AND payerReceiptID = 19781
  ) x
 JOIN (SELECT t.rxID
      FROM
       (
   SELECT IsInstyRxFlag,   pri.payerReceiptItemId,           CONVERT(varchar,rx.oeDate, 101) rxOeDate,  CONVERT(DECIMAL(6,2), drx.payerOblig) payerObligation,    CONVERT(DECIMAL(6,2), pri.amountPaid) amountPaid,  pri.rxId,    CONVERT(DECIMAL(6,2), (pri.amountPaid - drx.payerOblig)) difference, rxeventid  
   FROM PayerReceiptItem pri 
  JOIN Rx ON rx.rxId = pri.rxId 
 JOIN DispenseRx drx ON rx.rxId = drx.rxId  
  WHERE CONVERT(DECIMAL(6,2), drx.payerOblig) <>  CONVERT(DECIMAL(6,2), pri.amountPaid)      AND payerReceiptID = 19781
 ) t

  GROUP BY t.rxID
     HAVING COUNT(t.rxID) > 1) y ON  y.rxID = x.rxid

     --can't find y.amountpaid, x can be seen
     --and y.amountPaid = x.amountPaid

现在使用它，但x.amount支付无效，因为它不是聚合函数。

with 
x AS (SELECT IsInstyRxFlag
, pri.payerReceiptItemId
, CONVERT(varchar,rx.oeDate, 101) rxOeDate
, CONVERT(DECIMAL(6,2), drx.payerOblig) payerObligation
, CONVERT(DECIMAL(6,2), pri.amountPaid) amountPaid
, pri.rxId
, CONVERT(DECIMAL(6,2), (pri.amountPaid - drx.payerOblig)) difference
, rxeventid  
FROM PayerReceiptItem pri 
 JOIN Rx ON rx.rxId = pri.rxId 
JOIN DispenseRx drx ON rx.rxId = drx.rxId  
WHERE CONVERT(DECIMAL(6,2), drx.payerOblig) <>  CONVERT(DECIMAL(6,2), pri.amountPaid) AND payerReceiptID = 19781)
SELECT x.*
 FROM x


   where not exists(
   SELECT * 
    FROM x AS y
    WHERE x.amountpaid = -1* y.amountpaid
  AND x.difference = x.amountpaid 
  AND x.rxid = y.rxid 
   );

Answer 1

您期望得到什么结果？我简化了你的查询，看看这个：

with 
  x AS (SELECT IsInstyRxFlag
  , pri.payerReceiptItemId
  , CONVERT(varchar,rx.oeDate, 101) rxOeDate
  , CONVERT(DECIMAL(6,2), drx.payerOblig) payerObligation
  , CONVERT(DECIMAL(6,2), pri.amountPaid) amountPaid
  , pri.rxId
  , CONVERT(DECIMAL(6,2), (pri.amountPaid - drx.payerOblig)) difference
  , rxeventid  
  FROM PayerReceiptItem pri 
  JOIN Rx ON rx.rxId = pri.rxId 
  JOIN DispenseRx drx ON rx.rxId = drx.rxId  
  WHERE CONVERT(DECIMAL(6,2), drx.payerOblig) <>  CONVERT(DECIMAL(6,2), pri.amountPaid) AND payerReceiptID = 19781)
SELECT x.*
FROM x
JOIN (
  SELECT t.rxID -- how you want to find amountpaid if you don't select this
  --you can select max or min from amountpaid, to not group by this field
  , min(amountpaid) min_amountpaid, max(amountpaid) max_amountpaid
  FROM x t
  GROUP BY t.rxID
  HAVING COUNT(t.rxID) > 1) y 
ON  y.rxID = x.rxid

修改但如果您只需要排除这两行，请尝试以下查询：

with x AS (SELECT IsInstyRxFlag , pri.payerReceiptItemId , CONVERT(varchar,rx.oeDate, 101) rxOeDate , CONVERT(DECIMAL(6,2), drx.payerOblig) payerObligation , CONVERT(DECIMAL(6,2), pri.amountPaid) amountPaid , pri.rxId , CONVERT(DECIMAL(6,2), (pri.amountPaid - drx.payerOblig)) difference , rxeventid FROM PayerReceiptItem pri JOIN Rx ON rx.rxId = pri.rxId JOIN DispenseRx drx ON rx.rxId = drx.rxId WHERE CONVERT(DECIMAL(6,2), drx.payerOblig) <> CONVERT(DECIMAL(6,2), pri.amountPaid) AND payerReceiptID = 19781) SELECT x.* FROM x WHERE NOT EXISTS (SELECT 1 FROM x t WHERE t.rxID = x.rxID and t.amountPaid = -1 * x.amountPaid )

如何返回删除了与两列匹配的SQL行的表

1 个答案: