Question

我试图在Android中创建一个天气应用程序，我从用户那里得到输入，然后告诉他们当前的天气。主要活动看起来像这样

package com.example.dellinspiron.speechrecognition;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;

import android.graphics.Typeface;
import android.text.Html;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

    TextView cityField, detailsField, currentTemperatureField, humidity_field, pressure_field, weatherIcon, updatedField;

    Typeface weatherFont;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        getSupportActionBar().hide();
        setContentView(R.layout.activity_main);


        Button b=(Button)findViewById(R.id.button);
        assert b != null;
        b.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                EditText c=(EditText)findViewById(R.id.city);
                EditText d=(EditText)findViewById(R.id.country);
                final String city=c.getText().toString();
                final String country=d.getText().toString();


                weatherFont = Typeface.createFromAsset(getApplicationContext().getAssets(), "fonts/weathericons-regular-webfont.ttf");

                cityField = (TextView)findViewById(R.id.city_field);
                updatedField = (TextView)findViewById(R.id.updated_field);
                detailsField = (TextView)findViewById(R.id.details_field);
                currentTemperatureField = (TextView)findViewById(R.id.current_temperature_field);
                humidity_field = (TextView)findViewById(R.id.humidity_field);
                pressure_field = (TextView)findViewById(R.id.pressure_field);
                weatherIcon = (TextView)findViewById(R.id.weather_icon);
                weatherIcon.setTypeface(weatherFont);


                Function.placeIdTask asyncTask =new Function.placeIdTask(new Function.AsyncResponse() {
                    public void processFinish(String weather_city, String weather_description, String weather_temperature, String weather_humidity, String weather_pressure, String weather_updatedOn, String weather_iconText, String sun_rise) {

                        cityField.setText(weather_city);
                        updatedField.setText(weather_updatedOn);
                        detailsField.setText(weather_description);
                        currentTemperatureField.setText(weather_temperature);
                        humidity_field.setText("Humidity: "+weather_humidity);
                        pressure_field.setText("Pressure: "+weather_pressure);
                        weatherIcon.setText(Html.fromHtml(weather_iconText));

                    }
                });
                asyncTask.execute(city, country); // having problems here
            }
        });



    }

当我尝试明确传递城市名称和国家时，例如asyncTask.execute（＆＃34; rawalpindi＆＃34;，＆＃34;巴基斯坦＆＃34;）它可以工作，但是如果我尝试传递一个字符串获得从文本框中它没有。我试图得到字符串的输出，它给出了正确的输出，但它只是没有正确传递给执行函数。请帮忙。

Answer 1

当您从EditText获取文本时，尝试使用trim方法trim()字符串，因为额外的空格可能会导致结果中的错误。

在android中将字符串传递给AsyncTask.execute？

1 个答案: