我在listviews中获取重复值,但我确信在我使用的列表中没有重复项。
以下是代码,
public class MainActivity extends Activity {
ArrayList<String> listOfSongs = new ArrayList<String>();
ListView liststructure;
final private int REQUEST_CODE_ASK_PERMISSIONS = 123;
String MUSIC_STRING = MediaStore.Audio.Media.IS_MUSIC + "!=0";
String[] STAR = {"*"};
Uri uri=null;
String orderColumns = MediaStore.Audio.AudioColumns.TITLE + " COLLATE LOCALISED ASC";
private final int REQUEST_GRANTED_BY_USER = 1;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
liststructure = (ListView) findViewById(R.id.listView);
SongsList list = new SongsList(MainActivity.this, listOfSongs);
liststructure.setAdapter(list);
checkPermissions();
Toast.makeText(getApplicationContext(), "Total number of Items are:" + liststructure.getAdapter().getCount() , Toast.LENGTH_LONG).show();
}
private void checkPermissions() {
if (Build.VERSION.SDK_INT >= 23) {
int permissionCheck = ContextCompat.checkSelfPermission(MainActivity.this,
Manifest.permission.READ_EXTERNAL_STORAGE);
if (permissionCheck != PackageManager.PERMISSION_GRANTED) {
ActivityCompat.requestPermissions(MainActivity.this,
new String[]{Manifest.permission.READ_EXTERNAL_STORAGE}, REQUEST_GRANTED_BY_USER);
}else{
getInfoFromDevice();
}
}else{
getInfoFromDevice();
}
}
void getInfoFromDevice() {
uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
Cursor cursor = getContentResolver().query(uri, STAR, MUSIC_STRING, null, null);
if (cursor != null)
{
if (cursor.moveToFirst()) {
do {
String name = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Media.DISPLAY_NAME));
String data = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Media.DATA));
String album = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Media.ALBUM));
String albumID = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Media.ALBUM_ID));
listOfSongs.add(name);
} while (cursor.moveToNext());
}
Log.d("COUNT","COUNT is " + listOfSongs.size());
}
listOfSongs.size();
}
}
SongList.java
public class SongsList extends BaseAdapter {
ArrayList<String> songs;
Context c;
SongsList(Context c, ArrayList<String> songs)
{
this.c=c;
this.songs = songs;
}
@Override
public int getCount() {
return songs.size();
}
@Override
public Object getItem(int i) {
return songs.get(i);
}
@Override
public long getItemId(int i) {
return i;
}
@Override
public View getView(int i, View view, ViewGroup viewGroup) {
TextView tv;
ViewHolder vh;
LayoutInflater inflater = (LayoutInflater)
c.getSystemService(Activity.LAYOUT_INFLATER_SERVICE);
if(view ==null)
{
view = inflater.inflate(R.layout.green,viewGroup,false);
vh = new ViewHolder(view);
view.setTag(vh);
vh.tv.setText(songs.get(i));
}
else{
vh = (ViewHolder) view.getTag();
}
return view;
}
}
我也尝试过以下问题,
Duplicated entries in ListView
结果:我已经实现了这一点。
Android ListView Duplicates entries
结果:这不起作用。
All elements of An ArrayList change when a new one is added?
结果:没有循环和对象创建代码。
结果:已经实现了这一点。
有没有人能告诉我为什么列表视图会显示重复项?
答案 0 :(得分:0)
您需要在视图已存在时设置文本视图内容:
} else {
vh = (ViewHolder) view.getTag();
vh.tv.setText(songs.get(i));
}
答案 1 :(得分:0)
我认为解决方案实际上是您链接的第一个答案。
尝试将代码更改为:
if(view ==null)
{
view = inflater.inflate(R.layout.green,viewGroup,false);
vh = new ViewHolder(view);
view.setTag(vh);
vh.tv.setText(songs.get(i));
}
else{
vh = (ViewHolder) view.getTag();
vh.tv.setText(songs.get(i));
}
在else语句中,您正在重用已创建的视图,但仍需要更新该视图中的数据。