api需要在一些字段中使用post请求,但我不知道字段将被添加到哪里!! (在GET请求中,我像在任何请求中一样添加url中的字段)
api代码
`
$apiKey = "8z8a7tupn5hubhjxqh8ubuz7";
$sharedSecret = "jsSJq2msbU";
$signature = hash("sha256", $apiKey.$sharedSecret.time());
$endpoint = "https://api.test.hotelbeds.com/activity-api/3.0/activities";
$request = new \http\Client\Request("POST",
$endpoint,
[ "Api-Key" => $apiKey,
"X-Signature" => $signature,
"Accept" => "application/json" ,
]);
$client = new \http\Client;
$client->enqueue($request)->send();
$response = $client->getResponse();
echo "<pre>";
print_r($response->getBody());
echo "</pre>";
api说
下面列出了搜索的可用过滤器。
它包含一个具有以下结构的过滤器数组:
[{&#34; searchFilterItems&#34;:[{&#34; type&#34;:&#34; destination&#34;,&#34; value&#34;:&#34; BCN&#34 ;}]}]
对象“searchFilterItems”包含以下属性:type&gt;和价值。
以下示例说明了&gt;的不同类型和值。每个过滤器:
国家
{&#34; type&#34;:&#34; country&#34;,&#34; value&#34;:&#34; PT&#34;}
答案 0 :(得分:2)
我有同样的问题,花了一点时间弄明白。事实证明,您需要使用Body类来表示发布数据。
$msg = new http\Message\Body();
$msg->addForm([
'field1' => 'value',
'field2' => 'value2'
]);
$headers = null;
$request = new http\Client\Request('POST', 'https://example.com', $headers, $msg);
$client = new http\Client();
$client->enqueue($request);
$client->send();
$response = $client->getResponse();
Message和Body类中还有一些方法可用于包含文件等。
答案 1 :(得分:1)
试试这种方式
$request = new http\Client\Request;
$body = new http\Message\Body;
$body->append('{Your JSON}');
$request->setRequestUrl('https://api.hotelbeds.com/hotel-api/1.0 hotels');
$request->setRequestMethod('POST');
$request->setBody($body);
$request->setHeaders(array(
'Accept' => 'application/json',
'Content-Type' => 'application/json',
'Api-Key' => $owapiKey,
'X-Signature' => $signature,
//'Accept-Encoding' => 'Gzip', //Deflate
'cache-control' => 'no-cache'
));
try {
$client = new http\Client;
$client->enqueue($request)->send();
$response = $client->getResponse();
if ($response->getResponseCode() != 200) {
echo("HTTP CONNECT FAILURE: -> ".
$response->getTransferInfo("effective_url").
$response->getInfo().$response->getResponseCode() );
} else {
$res=$response->getBody()->toString();
}
} catch (Exception $ex) { echo("Error while sending request, reason: %s\n".$ex->getMessage()); }