我在函数中使用foreach但是,我无法从中输出正确的值。
我有一个由函数
处理的数组//this is only a small part of it because it is very large
Array
(
[2016-05-02] => Array
(
[grup_1] => Array
(
[luce] => 4
[ctr_ok] => 3
[ctr_tot] => 7
[ctr_ko] => 4
[gas] => 3
[ore] => 30.5
)
[grup_2] => Array
(
[luce] => 3
[ctr_ko] => 4
[ctr_tot] => 6
[gas] => 3
[ctr_ok] => 2
[ore] => 47
)
[grup_3] => Array
(
[luce] => 6
[ctr_ko] => 1
[ctr_tot] => 8
[ctr_gia_cliente] => 1
[ctr_ok] => 6
[gas] => 2
[ore] => 24
)
[grup_4] => Array
(
[luce] => 4
[ctr_ok] => 4
[ctr_tot] => 8
[gas] => 4
[ctr_ko] => 4
[ore] => 30
)
[grup_5] => Array
(
[luce] => 9
[ctr_ko] => 11
[ctr_tot] => 17
[gas] => 8
[ctr_ok] => 6
[ore] => 35
)
[grup_6] => Array
(
[luce] => 1
[ctr_ok] => 2
[ctr_tot] => 2
[gas] => 1
[ore] => 36
)
[grup_7] => Array
(
[luce] => 5
[ctr_ko] => 1
[ctr_tot] => 7
[ctr_ok] => 6
[gas] => 2
[ore] => 22
)
)
[2016-05-03] => Array
(
[grup_1] => Array
(
[luce] => 6
[ctr_ok] => 6
[ctr_tot] => 10
[gas] => 4
[ctr_ko] => 4
[ore] => 33.5
)
[grup_2] => Array
(
[luce] => 6
[ctr_ok] => 4
[ctr_tot] => 8
[ctr_ko] => 2
[gas] => 2
[ctr_att_green] => 2
[ore] => 36
)
[grup_3] => Array
(
[luce] => 6
[ctr_ok] => 4
[ctr_tot] => 9
[gas] => 3
[ctr_ko] => 5
[ore] => 36
)
[grup_4] => Array
(
[luce] => 5
[ctr_ko] => 2
[ctr_tot] => 10
[gas] => 5
[ctr_ok] => 8
[ore] => 42
)
[grup_5] => Array
(
[gas] => 2
[ctr_ok] => 3
[ctr_tot] => 3
[luce] => 1
[ore] => 23
)
[grup_6] => Array
(
[luce] => 1
[ctr_ko] => 2
[ctr_tot] => 2
[gas] => 1
[ore] => 36
)
[grup_7] => Array
(
[luce] => 2
[ctr_ok] => 1
[ctr_tot] => 3
[ctr_gia_cliente] => 2
[gas] => 1
[ore] => 27.3
)
)
这是收集ctr_tot
密钥
function kontratat_tot($grup_name){
$total = 0;
foreach ($kontrata as $date => $grup){
if($grup[$grup_name]['ctr_tot'] != 0){
$total += $grup[$grup_name]['ctr_tot'];
}
}
return $total;
}
在这里我调用函数
kontratat_tot("grup_1");
我一直在寻找过去3个小时为我的问题找到任何解决方案,但我已经卡住了,即使解决方案是从我的眼睛出来我也看不到它。
答案 0 :(得分:1)
$kontrata
是kontratat_tot
函数的outside the scope。尝试将其指定为global
,或传入您的函数。
function kontratat_tot($grup_name)
{
global $kontrata;
$total = 0;
foreach( $kontrata as $date => $grup )
{
if($grup[$grup_name]['ctr_tot'] != 0)
{
$total += $grup[$grup_name]['ctr_tot'];
}
}
return $total;
}
答案 1 :(得分:1)
您的函数正在尝试访问不属于当前范围但位于父范围内的$kontrata
。
我建议你将数据作为参数传递,定义全局变量并在函数内访问它将限制你使用相同的变量名,如果你想使用这个函数两次或更多。
function kontratat_tot($kontrata, $grup_name){
$total = 0;
foreach ($kontrata as $date => $grup){
if($grup[$grup_name]['ctr_tot'] != 0){
$total += $grup[$grup_name]['ctr_tot'];
}
}
return $total;
}