Question

我想使用Python Selenium登录此web site，我已编写此代码：

# -*- coding: utf-8 -*-
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.common.exceptions import NoSuchElementException
from selenium.common.exceptions import NoAlertPresentException
import unittest, time, re

class Mps(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Firefox()
        self.driver.implicitly_wait(30)
        self.base_url = "https://www.google.it/"
        self.verificationErrors = []
        self.accept_next_alert = True

    def test_mps(self):
        driver = self.driver
        driver.get(self.base_url + "/portaleTitolari/titolari.html")
        driver.find_element_by_id("ext-gen30").clear()
        driver.find_element_by_id("ext-gen30").send_keys("username33")
        driver.find_element_by_id("ext-gen11").clear()
        driver.find_element_by_id("ext-gen11").send_keys("password33")
        driver.find_element_by_id("ext-gen38").click()

    def is_element_present(self, how, what):
        try: self.driver.find_element(by=how, value=what)
        except NoSuchElementException as e: return False
        return True

    def is_alert_present(self):
        try: self.driver.switch_to_alert()
        except NoAlertPresentException as e: return False
        return True

    def close_alert_and_get_its_text(self):
        try:
            alert = self.driver.switch_to_alert()
            alert_text = alert.text
            if self.accept_next_alert:
                alert.accept()
            else:
                alert.dismiss()
            return alert_text
        finally: self.accept_next_alert = True

    def tearDown(self):
        self.driver.quit()
        self.assertEqual([], self.verificationErrors)

if __name__ == "__main__":
    unittest.main()

问题是用户名和密码输入字段名称每次都会更改。在这种情况下，如何找到用户名，密码输入字段和登录按钮？

Answer 1

这两个输入字段似乎都有静态类。只需使用xpath搜索具有给定类的输入元素。类似的东西：

driver.find_element_by_xpath("//input[@class='login_component_input']")

由于密码使用相同的类，您可以尝试在查询中包含元素类型：

driver.find_element_by_xpath("//input[@class='login_component_input' and @type='password']")

xpath是一种非常富有表现力的语言。如果你要自动化网站，你应该花一些时间来理解它。

使用Python Selenium登录网站

1 个答案: