Question

我想根据用户输入从Django模型（mysql）获取数据。就像我有一个html搜索选项卡，用户将放置搜索值，该值应该从Django模型获取相关数据并显示在另一个html页面中。我试过但失败了。请帮忙..

views.py

 from django.shortcuts import render_to_response
 from django.http import HttpResponse
 from hello.models import Techstop 
 # Create your views here.

 def search(request):
      return render_to_response('search.html')


 def results(request):
    if 'q' in request.GET and request.GET['q']:
            q=request.GET['q']
            name=Techstop.objects.filter(City=q)
            return render_to_response('results.html')
    else:
            return HttpResponse('Please enter a valid input.')


  models.py

  from django.db import models


  class Techstop(models.Model):
          Name = models.CharField(max_length=30)
          Email = models.CharField(max_length=50)
          City = models.CharField(max_length=20)
          Country = models.CharField(max_length=20)
          Dept = models.CharField(max_length=30)

    def __unicode__(self):
          return self.City


       search.html


     <!DOCTYPE html>
  <html>
  <head>
      <title>Search</title>
  </head>
  <body>
  <form action="/search/" method="get">
      <input type="text" name="q">
      <input type="submit" value="Search">
   </form>
  </body>
  </html>

   results.html

  {% if name %}
<ul>
    {% for n in name %}
    <li>{{ n.City }}</li>
    {% endfor %}
</ul>
 {% else %}
      <p>No name matched your search criteria.</p> 
 {% endif %}

Answer 1

渲染任何模板时，需要将所需的所有变量作为上下文字典传递。

return render_to_response('results.html', {'name': name})

本教程中对此进行了解释;你应该去追随它。

Answer 2

假设您使用GET方法提交表单：

def results(request):
    q = request.GET.get('q', None)
    if q:
        # icontains work similar to LIKE keyword in mysql.
        # for exact text search you can directly search City=q
        name=Techstop.objects.filter(City__icontains=q)

        # {'name': name} is the context that we attach with the html to render.
        return render_to_response('results.html', {'name': name})
    else:
        return HttpResponse('Please enter a valid input.')

您还可以使用Q对象进行更多的comples搜索。

Answer 3

您只需使用以下功能即可：

            projectArrayList = projectAdapter.projectItems;
            projectAdapter = new ProjectAdapter(getActivity(), projectArrayList);
            setListAdapter(projectAdapter);
            getListView().setOnItemClickListener(this);
            projectAdapter.sort(new Comparator<ProjectItem>() {
                @Override
                public int compare(ProjectItem lhs, ProjectItem rhs) {
                    return lhs.getPriority() - rhs.getPriority();
                }
            });
            projectAdapter.notifyDataSetChanged();

用法示例：

import re
from django.db.models import Q

def normalize_query(query_string,
                    findterms=re.compile(r'"([^"]+)"|(\S+)').findall,
                    normspace=re.compile(r'\s{2,}').sub):

    return [normspace(' ', (t[0] or t[1]).strip()) for t in findterms(query_string)] 

def get_query(query_string, search_fields):
    ''' Returns a query, that is a combination of Q objects. That combination
        aims to search keywords within a model by testing the given search fields.

    '''
    query = None # Query to search for every search term        
    terms = normalize_query(query_string)
    for term in terms:
        or_query = None # Query to search for a given term in each field
        for field_name in search_fields:
            q = Q(**{"%s__icontains" % field_name: term})
            if or_query is None:
                or_query = q
            else:
                or_query = or_query | q
        if query is None:
            query = or_query
        else:
            query = query & or_query
    return query

希望它有所帮助!!

根据用户搜索从Django模型（mysql）获取数据

3 个答案: