Question

接收错误，例如非唯一表/别名：＆＃39; provinces＆＃39; ，下面的函数是模型函数，我在模型中创建这个函数但是得到错误表/别名

function get_data_three_tbl(){

                $this->db->select('blood_donors.id, blood_donors.full_name, blood_donors.area, blood_donors.email, blood_donors.phone, provinces.province_name,districts.district_name, tehsils.tehsil_name, blood_groups.group_name');
                $this->db->from ( 'blood_donors, provinces, districts, tehsils, blood_groups ' );
                $this->db->where('blood_donors.is_deleted',1);
                $this->db->join('provinces','provinces.province_id = blood_donors.province');
                $this->db->join('districts','districts.district_id = blood_donors.district');
                $this->db->join('tehsils','tehsils.tehsil_id = blood_donors.tehsil');
                $this->db->join('blood_groups','blood_groups.id = blood_donors.blood_goup');
                $query = $this->db->get();
                if ($query->num_rows() > 0)
                return $query->result_array();
                else
                return FALSE;
    }

Answer 1

将from()来电更改为

$this->db->from('blood_donors');

join语句负责其他表。在from和join语句中包含表名是导致非唯一错误的原因。

使用SQL Join在Codeigniter中从多表中获取数据

1 个答案: