Question

我正在创建一个登录系统，由于某种原因，即使我输入了正确的电子邮件和密码，它也会重定向回登录页面。被调用的模型函数似乎不起作用。这是我的代码：

控制器：

<?php
defined('BASEPATH') OR exit('No direct script access allowed');
    class Login extends CI_Controller {



        function validation()
        {

            $this->load->library('form_validation');

            $this->form_validation->set_rules('email', 'Email', 'required|trim');
             $this->form_validation->set_rules('password', 'Password', 'required|md5');



            if ($this->form_validation->run()){

                redirect('login/valid_credentials'); 

            }else{

              $this->load->view('login_form');
              //return false;    
            }

        }




        function valid_credentials(){

           $this->load->model('login_model');
            // oh i see

             if ($this->login_model->match_login()){
                //return true;
                 $data = array(
                    'id'=>$q['id'], 

                    'email'=>$this->input->post('email'),
                  'is_logged_in'=> 1);
                $this->session->set_userdata($data);
                $this->load->view('dashboard_view', $data);

           }else{
                 $this->load->view('login_form');


            }

       }

型号：

class Login_model extends CI_Model{

    public function match_login(){

        $this->db->where('email', $this->input->post('email'));
        $this->db->where('password', md5($this->input->post('password')));
        $q = $this->db->get('user');

        if($q->num_rows()== 1){

          return true;

        }
    }
}

查看：

<?php

echo "<h1 class ='col-lg-10 col-lg-offset-5'>SIGN IN</h1>";


echo form_open('login/validation', $grid);


echo "<h2>Client</h2>";

"<h3>Please Login</h3>";

echo validation_errors();

echo "<p> Email: </br>";
echo form_input ('email');
echo "</p>";


echo "<p> Password: </br>";
echo form_password ('password');
echo "</p>";




echo "<p>";
echo form_submit ('submit', 'Signin');
 echo "</p>";

echo form_close();

?>

出于某种原因，它不起作用，我不确定我错过了什么。

Answer 1

无需在一个功能中验证表单，在另一个功能中检查登录。使用一个功能来做所有事情。

<强>更改

控制器代码更改和优化
型号代码已更改

部分参考资料

CodeIgniter Form Validation in FromGet.com（亲自推荐此网站）
Form Validation in Codeigniter.com

试试这个

<强>控制器

<?php
defined('BASEPATH') OR exit('No direct script access allowed');
    class Login extends CI_Controller {     

        function validation()
        {

            $this->load->library('form_validation');

            $this->form_validation->set_rules('email', 'Email', 'required|trim');
            $this->form_validation->set_rules('password', 'Password', 'required|md5');


            if ($this->form_validation->run()  == FALSE )
            {
                $this->load->view('login_form');
                //return false; 
            }
            else{

                $this->load->model('login_model');

                $email = $this->input->post('email');
                $password = $this->input->post('password');

                $result = $this->login_model->match_login($email, $password);

                if ($result ==false) {
                    echo "Invalid Cardinals";
                 } 
                 else 
                 {
                    $session = array(
                      'id'=>$result[0]['id'], 
                      'email'=>$this->input->post('email'),
                      'is_logged_in'=> 1
                    );
                    if (!$this->session->set_userdata($session)) {

                        $data['modelData'] = $result;
                        $data['sessionData'] = $session;

                        $this->load->view('dashboard_view', $data);
                    }
                     else {
                        echo "Error in session";.
                    }                          
                }   
            }            
        }

<强>模型

class Login_model extends CI_Model{

    public function match_login($email, $password){

        $this->db->where('email', $email);
        $this->db->where('password', md5($password));
        $query = $this->db->get('user');

        $result = $query->result_array();

        if (empty($result)) 
        {
            return false;
        } 
        else 
        {
            return $result;
        }

    }
}

尝试使用数据库验证用户信息时，Codeigniter功能不起作用

1 个答案: