PHP命令行输出和浏览器/卷曲是不同的

Question

我的脚本设计如下 -

服务器列表放在-servers.txt。

servera01
servera02
servera03
serverb01
serverb02
serverb03

我的shell脚本是-status_check1.sh

#!/bin/bash
for i in `cat servers.txt`; do
   ssh -q  sv-p-jb@$i ls -l /apps/jboss/welcome-content/keepAlive.html > /dev/null
 #server="$i"
 if [ $? == 0 ]; then

     echo -e "Server $i is in VIP  | \n"
 else
     echo -e "Server $i is not in VIP | \n"
 fi

done

我的php脚本是-test.php

<?php
exec('./status_check1.sh', $output);
#echo implode("\n", $output);
$myarray = explode('|', implode($output));
$arr_length = count($myarray);
for($i=0;$i<$arr_length;$i++)
{
echo $myarray["$i"];
echo "<br />";
echo "\r\n";
}
?>

我将php命令行（php test.php）输出为 -

servera01 is in VIP  |
servera02 is in VIP  |
servera03 is in VIP  |
serverb01 is in VIP  |
serverb02 is in VIP  |
serverb03 is in VIP  |

但是当我在浏览器上访问它时，低于输出。

servera01 is not in VIP  
servera02 is not in VIP  
servera03 is not in VIP  
serverb01 is in VIP  
serverb02 is in VIP  
serverb03 is in VIP  

你能否告诉我为什么这种不同的输出会出现在浏览器中。 我无法理解，相同的shell脚本如何在浏览器中返回'not'。

感谢。