Question

我一直在应该更新DB中的表的块上获得sql语法错误。我尝试了几种不同的方法来编写语法，并尝试不使用预准备语句。我有一个显示movietitles的表格，其中包含编辑和选项的选项。删除。选择编辑时，它会抓取ID＆gt;检查数据＆gt;在表单中显示正确的数据。到现在为止还挺好。但是当我点击更新时，由于语法错误，查询不想运行。我怀疑其他事情可能是它不会运行的原因。

＆＃13;

<!DOCTYPE html>
<html>
<head>
	<meta charset="UTF-8">
	<title></title>
</head>
<body>
<?php
require_once ('dbinfo.php');

/*This block gets Id from the URL in the movietitle that is being edited
  and displays the data in the form */
$id = filter_input(INPUT_GET, 'id', FILTER_SANITIZE_SPECIAL_CHARS);
$query3 = "SELECT * FROM movie WHERE id=$id";
$result = $con->query($query3);
if (!$result) die($con->error);
$row = mysqli_fetch_array($result);

$title = $row['title'];
$director = $row['director'];
$year = $row['year'];
$category = $row['categoryid'];

//This block updates the moviedata if the submitbutton is pressed 
if (isset($_POST['update'])) {

$query = "UPDATE movie SET 'title'=?, 'director'=?, 'year'=?, 'categoryid'=? WHERE 'id'=$id";

if (!$stmt = $con->prepare($query)) {
	echo "Prepare failed: (" . $con->errno . ") " . $con->error;
}

if (!$stmt->bind_param("ssii", $_POST['title'], $_POST['director'], $_POST['year'], $_POST['categoryid'])) {
	echo "Binding parameters failed: (" . $stmt->errno . ") " . $stmt->error;
}

if (!$stmt->execute()) {
	echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;	
}

//Returns to the mainform after update is done
header('Location: form.php');

}
?>

<form method="post" action="edit.php">
<fieldset> <legend>Edit movie</legend>
	<input type="radio" name="category" value="1" <?php if ($category=="1") echo "checked"; ?>> Sci-Fi<br>
	<input type="radio" name="category" value="2" <?php if ($category=="2") echo "checked"; ?>> Horror<br>
	<input type="radio" name="category" value="3" <?php if ($category=="3") echo "checked"; ?>> Thriller<br>
	<input type="radio" name="category" value="4" <?php if ($category=="4") echo "checked"; ?>> Comedy<br>
	<input type="radio" name="category" value="5" <?php if ($category=="5") echo "checked"; ?>> Fantasy<br><br>

	<input type="text" id="title" name="title" maxlength="50" placeholder="Title" value="<?php echo $title; ?>" required> <br>
	<input type="text" id="director" name="director" maxlength="50" placeholder="Director" value="<?php echo $director; ?>" required><br>
	<input type="text" id="year" name="year" maxlength="4" placeholder="Year" value="<?php echo $year; ?>" required><br><br>
	<input type="submit" value="Update" name="update" id="update">
</fieldset>	
</form>

</body>
</html>

＆＃13;

更新db

0 个答案: