Question

过程ReadVal应该循环并要求用户输入10个整数（AS STRINGS），最终将每个整数存储在一个数组中。 ReadVal使用宏getString，它第一次工作。然后其他9次打印“请输入无符号整数：”但不停止允许用户输入值。因此，它肯定会调用宏，但为什么它不会停止并等待接下来的9次输入。

INCLUDE Irvine32.inc
LEN = 10    ; Number of elements in array.

getString   MACRO   buffer, size
    push eax
    push ecx
    push edx
    mov edx,    OFFSET  userMsg_2
    call WriteString
    mov edx, buffer             ; buffer passed by reference, so no OFFSET req'd.
    mov eax, size
    mov ecx, [eax]              ; Dereference sizeElem to ecx counter.
    call ReadString
    pop edx
    pop ecx
    pop eax
ENDM

.data
userMsg_2   BYTE        "Please enter an unsigned number: ",0
array DWORD LEN dup(?)
    arLength    DWORD   LEN
    sizeElem    BYTE    11      ; Number of digits allowed in. reading ints as strings.
    holder  DWORD   ?           ; Temp memory location for storing string input/output.
.code
main PROC
    push OFFSET array
    push OFFSET arLength
    push OFFSET sizeElem
    push OFFSET holder
    call ReadVal
exit
main ENDP

ReadVal PROC
    push ebp
    mov ebp, esp
    push ecx
    mov esi, [ebp+20]               ; esi has starting address of array.
    mov eax, [ebp+16]               ; @arLength
    mov ecx, [eax]                  ; ecx gets arLength.
    cmp ecx, 0
    je L2
L1:
    getString [ebp+8], [ebp+12]  ; [ebp+8] gets the user inputted string.
    mov esi,    [ebp+8]          ; mov string in holder into array[esi].
    add esi, TYPE   DWORD
    loop L1
L2:
    pop ecx
    pop ebp
    ret 16
ReadVal ENDP
END main

Answer 1

我认为问题是ReadString期望ECX中的值是DWORD。将它作为BYTE给出一个数字令人困惑。将sizeElem声明为DWORD可以解决问题。

您可能希望将持有者声明为使用BYTE而不是DWORD，我认为这更常见于字符串存储。

循环中的宏工作一次，然后不

1 个答案: