我正在尝试为自定义内容管理解决方案实现自定义 HttpTaskAsyncHandler 。我的想法是将 / 100 / my-little-pony 路由到 / Details / my-little-pony 。我希望通过以下 HttpTaskAsyncHandler 实现此目的:
public override async Task ProcessRequestAsync(HttpContext context)
{
try
{
var id = GetContentIdFromRouteData();
// Retrieve the content identified by the specified ID
var contentRepository = new ContentRepository();
var content = await contentRepository.GetAsync(id);
if (content == null)
throw new ContentNotFoundException(id);
// Initialize an instance of the content controller
var factory = ControllerBuilder.Current.GetControllerFactory();
var controller = (IContentController) factory.CreateController(_requestContext, content.ControllerName);
if (controller == null)
throw new ControllerNotFoundException(content.ControllerName);
try
{
// Retrieve all content type values and pass them on the the method for index pages
var action = _requestContext.RouteData.GetRequiredString("action");
if (action == "Index")
{
ContentType data = null;
if (controller.ContentType != null)
{
data = BusinessHost.Resolve<ContentType>(controller.ContentType);
data.Values = content.Parameters.ToDictionary(p => p.Name, p => p.Value);
}
_requestContext.RouteData.Values.Add("data", data);
}
var values = _requestContext.RouteData.Values;
values.Add("name", content.Name);
values.Add("controllerId", id);
values.Add("controller", content.ControllerName);
controller.Execute(_requestContext);
}
finally
{
factory.ReleaseController(controller);
}
}
catch (ContentNotFoundException ex)
{
Trace.TraceWarning($"404: {ex.Message}");
_requestContext.HttpContext.Response.StatusCode = (int)HttpStatusCode.NotFound;
}
}
这对于同步请求非常有效,但是当我尝试调用异步方法时......
@using (Html.BeginForm("Save", Html.ControllerId(), FormMethod.Post, new { @class = "form-horizontal" }))
......这就是方法......
[HttpPost]
public async Task<ActionResult> Save(NewsViewModel model)
{ }
修改我已将方法的名称更改为保存,因为 Async 未被推断,我收到了新错误:
异步操作方法&#39;登录&#39;返回一个无法同步执行的任务。
答案 0 :(得分:2)
操作名称为SaveAsync
,但引用它的代码使用Save
作为名称。任何动作都没有神奇的重命名,包括异步一次。
您的选择:
SaveAsync
来引用操作ActionName
attribute重命名操作Save
(但这违反了所有async
方法都有...Async
后缀的惯例)旁注:对于重定向,使用路由可能比某些自定义处理程序更好。
答案 1 :(得分:0)
MvcHandler 还远远超出了人们的视线,而且我已经意识到人们不能简单地希望以干净的良心来复制它。因此,我决定改变完全解决这个问题的方式:而不是尝试实现我自己的 MvcHandler ,而是扩展我的 IRouteHandler 。
这是我的解决方案:
private static ConcurrentDictionary<string, Type> _contentTypes = new ConcurrentDictionary<string, Type>();
public IHttpHandler GetHttpHandler(RequestContext requestContext)
{
// Retrieve the page ID from the route data
var id = GetContentIdFromRouteData(requestContext);
// Retrieve the content identified by the specified ID
var contentRepository = new ContentRepository();
var content = contentRepository.Get(id);
if (content == null)
throw new ContentNotFoundException(id);
// Retrieve all content type values and pass them on the the method for index pages
var action = requestContext.RouteData.GetRequiredString("action");
if (action == "Index")
{
var data = CreateContentType(requestContext, content);
requestContext.RouteData.Values.Add("data", data);
}
var values = requestContext.RouteData.Values;
values.Add("name", content.Name);
values.Add("controllerId", id);
values.Add("controller", content.ControllerName);
return new MvcHandler(requestContext);
}
private static int GetContentIdFromRouteData(RequestContext context)
{
var idString = context.RouteData.GetRequiredString("id");
int id;
if (!int.TryParse(idString, out id))
throw new ArgumentException("Content can't be loaded due to an invalid route parameter.", "id");
return id;
}
private static ContentType CreateContentType(RequestContext context, Content content)
{
Type type;
if (!_contentTypes.ContainsKey(content.ControllerName) ||
!_contentTypes.TryGetValue(content.ControllerName, out type))
{
var factory = ControllerBuilder.Current.GetControllerFactory();
var controller = (IContentController)factory.CreateController(context, content.ControllerName);
if (controller == null)
throw new ControllerNotFoundException(content.ControllerName);
type = controller.ContentType;
factory.ReleaseController(controller);
_contentTypes.TryAdd(content.ControllerName, type);
}
ContentType data = null;
if (type != null)
{
data = BusinessHost.Resolve<ContentType>(type);
data.Values = content.Parameters.ToDictionary(p => p.Name, p => p.Value);
}
return data;
}