在字节数组中查找字节序列

时间:2016-05-28 15:10:20

标签: c# indexof

我有一个字节数组,希望找到"出现"一些字节。

例如00 69 73 6F 6D非常大的字节数组(> 50/100兆字节)

OR

更好的反向操作:在不知道代码的情况下搜索最常见的模式,代码应该能够从文件中读取并找到它。

1 个答案:

答案 0 :(得分:9)

您可以使用Boyer-Moore算法有效地搜索字节数组中的字节序列。

这是我从the Wikipedia entry on Boyer-Moore的Java版本转换而来的C#版本。

public sealed class BoyerMoore
{
    readonly byte[] needle;
    readonly int[] charTable;
    readonly int[] offsetTable;

    public BoyerMoore(byte[] needle)
    {
        this.needle = needle;
        this.charTable = makeByteTable(needle);
        this.offsetTable = makeOffsetTable(needle);
    }

    public IEnumerable<int> Search(byte[] haystack)
    {
        if (needle.Length == 0)
            yield break;

        for (int i = needle.Length - 1; i < haystack.Length;)
        {
            int j;

            for (j = needle.Length - 1; needle[j] == haystack[i]; --i, --j)
            {
                if (j != 0)
                    continue;

                yield return i;
                i += needle.Length - 1;
                break;
            }

            i += Math.Max(offsetTable[needle.Length - 1 - j], charTable[haystack[i]]);
        }
    }

    static int[] makeByteTable(byte[] needle)
    {
        const int ALPHABET_SIZE = 256;
        int[] table = new int[ALPHABET_SIZE];

        for (int i = 0; i < table.Length; ++i)
            table[i] = needle.Length;

        for (int i = 0; i < needle.Length - 1; ++i)
            table[needle[i]] = needle.Length - 1 - i;

        return table;
    }

    static int[] makeOffsetTable(byte[] needle)
    {
        int[] table = new int[needle.Length];
        int lastPrefixPosition = needle.Length;

        for (int i = needle.Length - 1; i >= 0; --i)
        {
            if (isPrefix(needle, i + 1))
                lastPrefixPosition = i + 1;

            table[needle.Length - 1 - i] = lastPrefixPosition - i + needle.Length - 1;
        }

        for (int i = 0; i < needle.Length - 1; ++i)
        {
            int slen = suffixLength(needle, i);
            table[slen] = needle.Length - 1 - i + slen;
        }

        return table;
    }

    static bool isPrefix(byte[] needle, int p)
    {
        for (int i = p, j = 0; i < needle.Length; ++i, ++j)
            if (needle[i] != needle[j])
                return false;

        return true;
    }

    static int suffixLength(byte[] needle, int p)
    {
        int len = 0;

        for (int i = p, j = needle.Length - 1; i >= 0 && needle[i] == needle[j]; --i, --j)
            ++len;

        return len;
    }
}

这里有一些控制台应用测试代码:

public static void Main()
{
    byte[] haystack = new byte[10000];
    byte[] needle = { 0x00, 0x69, 0x73, 0x6F, 0x6D };

    // Put a few copies of the needle into the haystack.

    for (int i = 1000; i <= 9000; i += 1000) 
        Array.Copy(needle, 0, haystack, i, needle.Length);

    var searcher = new BoyerMoore(needle);

    foreach (int index in searcher.Search(haystack))
        Console.WriteLine(index);
}

请注意Search()方法如何返回needlehaystack开头所有位置的索引。

如果您只是想要计数,您可以这样做:

int count = new BoyerMoore(needle).Search(haystack).Count();

对于你的第二个问题:我假设你问的是找到最长的重复字节序列?

这是一个更复杂,也是非常不同的问题。如果你想要一个答案,你应该问一个单独的问题,但你应该阅读the Wikipedia entry on the "longest repeated substring problem"