额外的争论'错误'在电话中
func handleReceivedDataWithNotification(notification:NSNotification){
let userInfo = notification.userInfo! as Dictionary
let receivedData:NSData = userInfo["data"] as! NSData
let message = NSJSONSerialization.JSONObjectWithData(receivedData, options: NSJSONReadingOptions.AllowFragments, error: nil) // This the error line
let senderPeerId:MCPeerID = userInfo["peerID"] as! MCPeerID
let senderDisplayName = senderPeerId.displayName
if message.objectForKey("string")?.isEqualToString("New Game") == true{
let alert = UIAlertController(title: "TicTacToe", message: "\(senderDisplayName) has started a new Game", preferredStyle: UIAlertControllerStyle.Alert)
alert.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.Default, handler: nil))
self.presentViewController(alert, animated: true, completion: nil)
resetField()
}else{
var field:Int? = message.objectForKey("field")?.integerValue
var player:String? = message.objectForKey("player") as? String
if field != nil && player != nil{
fields[field!].player = player
fields[field!].Player(player!)
if player == "x"{
currentPlayer = "o"
}else{
currentPlayer = "x"
}
checkResults()
}
}
}
答案 0 :(得分:1)
您可能正在尝试使用Swift 1.x编译器进行Swift 1.x调用。
Swift经历了1到2之间的大变化,现在该方法(以及报告错误的大多数其他方法)抛出异常而不是传入错误参数。
current documentation将签名显示为:
class func JSONObjectWithData(_ data: NSData,
options opt: NSJSONReadingOptions) throws -> AnyObject
要了解如何处理异常,请查看documentation。