我有一个名为电路的模型,每个电路可能有许多与之相关的文件。
所以在我看来我得到了所有电路和所有文件,然后我试图使用if语句来获取文件以匹配模板中的电路。
我试过了,下面但都回来了,我如何在模板中遍历模型找到匹配?
file.circuit_contract_data
file.circuit_contract_data__id
由于
view.py
@login_required
def showroom_detail(request, showroom_id):
modelShowroom = get_object_or_404(ShowroomConfigData, pk=showroom_id)
modelCircuits = CircuitInfoData.objects.filter(showroom_config_data=showroom_id)
modelCircuitFiles = CircuitFiles.objects.filter(circuit_contract_data__showroom_config_data=showroom_id)
modelSitePhotos = SitePhotos.objects.filter(showroom_config_data=showroom_id)
modelSiteFiles = SiteFiles.objects.filter(showroom_config_data=showroom_id)
return render(request, 'service/showroom_detail.html', {
'Showroom': modelShowroom,
'Circuits': modelCircuits,
'CircuitFiles': modelCircuitFiles,
'SitePhotos': modelSitePhotos,
'SiteFiles': modelSiteFiles,
})
模板
{% for item in Circuits %}
<tr class="{% cycle 'tr-1' 'tr-2' %}">
<td>{{ item.provider }}</td>
<td>{{ item.service_type }}</td>
<td>{{ item.circuit_speed }}</td>
<td>
{% for file in CircuitFiles %}
{% if file.circuit_contract_data == item.id %}
<a href ="{{ MEDIA_URL}}{{ file.circuit_file }}" target="_blank">{{ file.file_name }}</a><br />
{% endif %}
{% endfor %}
</td>
</tr>
模型
class CircuitInfoData(models.Model):
showroom_config_data = models.ForeignKey(ShowroomConfigData,verbose_name="Install Showroom",blank=True)
major_site_info = models.ForeignKey(MajorSiteInfoData,verbose_name="Install Site",blank=True)
service_type = models.ForeignKey(CircuitTypeInfoData)
circuit_speed = models.IntegerField(blank=True)
circuit_bearer = models.IntegerField(blank=True)
provider = models.CharField(max_length=200)
ref_no = models.CharField(max_length=200,verbose_name="Reference No")
install_location = models.CharField(max_length=200)
install_date = models.DateField()
cost_per_month = models.DecimalField(decimal_places=2,max_digits=8)
contract_length = models.IntegerField(verbose_name="Contact length in years")
notes = models.TextField(blank=True)
service_service_contacts = models.ForeignKey(ServiceContacts)
class Meta:
verbose_name = "Circuit Data"
verbose_name_plural = "Circuit Data"
ordering = ('showroom_config_data__location',)
def __unicode__(self):
return '%s | %s | %s | %s' % (self.showroom_config_data.location, self.provider, self.service_type, self.ref_no)
class CircuitFiles(models.Model):
circuit_contract_data = models.ForeignKey(CircuitInfoData,verbose_name="Showroom",blank=True)
circuit_file = models.FileField(blank=True,upload_to=service_upload_path)
file_name = models.CharField(max_length=200,verbose_name="File Name")
class Meta:
verbose_name = "Circuit Files"
verbose_name_plural = "Circuit Files"
ordering = ('circuit_contract_data',)
def __unicode__(self):
return self.file_name
答案 0 :(得分:4)
循环和比较对象是低效且不必要的,因为你可以query the foreign key relationship backwards这样:
{% for item in Circuits %}
<tr class="{% cycle 'tr-1' 'tr-2' %}">
<td>{{ item.provider }}</td>
<td>{{ item.service_type }}</td>
<td>{{ item.circuit_speed }}</td>
<td>
{% for file in item.circuitfiles_set.all %}
<a href ="{{ file.circuit_file.url }}" target="_blank">{{ file.file_name }}</a><br />
{% endfor %}
</td>
</tr>
{% endfor %}
然后,您可以从上下文中删除CircuitFiles
。您还可以使用url
的{{1}}属性,这样就不需要添加FileField
。
同样作为Python中的一般约定,只有类名称是驼峰式的 - 所有其他变量都是低级的。遵循此约定可以更容易区分该类的类和对象。