Question

我有2个字符串

[a,b,c]  //there could be any number of items in these 2 strings
[x,y,z]

我想要一个像这样的输出

a[x,y,z]
b[x,y,z]
c[x,y,z]

无法获得输出的逻辑。

Answer 1

要使用 map()

作为数组

var s1 = '[a,b,c]',
  s2 = '[x,y,z]';
console.log(
  s1
  .slice(1, -1) // remove the `[` and `]`
  .split(',') // split based on `,`
  .map(function(a) { // iterate and generate array
    return a + s2;
  })
)

要使用 reduce()

作为字符串

var s1 = '[a,b,c]',
  s2 = '[x,y,z]';
console.log(
  s1
  .slice(1, -1) // remove `[` and `]`
  .split(',') // split based on `,`
  .reduce(function(a, b) { // iterate and generate string
    return a + (a.length ? '\n' : ' ') + b + s2;
  }, '')
)

Answer 2

<?php

$s1 = '[a,b,c]';
$s2 = '[x,y,z]';

$items = explode(',', trim($s1, '[]'));
foreach ($items as $item) {
    echo($item . $s2 . "\n");
}

Answer 3

使用String.slice和String.replace函数的解决方案：

var keys = '[a,b,c,d,e]', values = '[x,y,z]',
    output = keys.slice(1, -1).replace(/([a-z]),?/g, function(m, p1){
        return p1 + values + "\n";
    });

console.log(output);

输出：

a[x,y,z]
b[x,y,z]
c[x,y,z]
d[x,y,z]
e[x,y,z]

将字符串的每个元素与第二个字符串组合在一起

3 个答案: