Question

我有这段代码：

$mainArray = Array(
[0] => Array
    (            
        [0] => 06
    )

[1] => Array
    (            
        [0] => 15
    )    
)
$array1 = array("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20"); 
$array2 = array_reverse($array1);

我想用$ array2的值递归替换$ mainArray的值（例如，当$ mainArray中的值等于15时替换为5,6替换为14。

我试过了：

foreach($mainArray $k1 => $value1){
    foreach($value1 as $k2 => $value2){ 

        $value2 = str_replace($array1,$array2,$value2);

        echo $value2;
    }
 }

但不能正常工作。

Answer 1

在第一个数组中查找索引，并从第二个数组中取值

$value2 = $array2[array_search($value2, $array1)];

或者算法总是相同的

$max = 20;
$value2 = $max - $value2;

Answer 2

您可能不需要其他阵列来执行此操作。如果我正确理解替换策略，您可以通过从20中减去原始值来获得替换值，从而以数学方式进行。

$replaced = array_map(function($x) {
    return array(20 - $x[0]);
}, $mainArray);

PHP - 替换多维数组的值

2 个答案: