如何将我的社交媒体按钮对齐到右上角

时间:2016-05-27 21:40:26

标签: php css

我想调整右上角的DISPLAY_ULTIMATE_PLUS社交媒体按钮。我尝试了几种对齐方法,但它似乎不起作用。这是代码。

<?php
/**
* The template for displaying the header
*
* Displays all of the head element and everything up until the 
"site-        content" div.
*
* @package WordPress
* @subpackage Twenty_Sixteen
* @since Twenty Sixteen 1.0
*/

?><!DOCTYPE html>
<html <?php language_attributes(); ?> class="no-js">
<head>
<meta charset="<?php bloginfo( 'charset' ); ?>">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="profile" href="http://gmpg.org/xfn/11">
<?php if ( is_singular() && pings_open( get_queried_object() ) ) : ?>
<link rel="pingback" href="<?php bloginfo( 'pingback_url' ); ?>">
<?php endif; ?>
<?php wp_head(); ?>
</head>

<?php echo DISPLAY_ULTIMATE_PLUS(); ?>
<?php echo do_shortcode("[huge_it_slider id='2']"); ?>
<div class='mailmunch-forms-widget-295732'></div>

1 个答案:

答案 0 :(得分:0)

申请:

position: absolute;

top: 0;
right: 0;
媒体按钮上的

,以及与position: relative;相对应的父<div>上的position: fixed; top: 0; right: 0;

应用:

style=""

在媒体按钮上。

您可以使用import numpy as np matrix = np.array([[1,1,1,1,1,0,0,0,0,0], #0 this is the board, it's represented by a 10x10 matrix [1,1,1,1,0,0,0,0,0,0], #1 the 0s represent empty spaces [1,1,1,0,0,0,0,0,0,0], #2 the 1s represent player 1's chips [1,1,0,0,0,0,0,0,0,0], #3 the 2s represetn player 2's chips [1,0,0,0,0,0,0,0,0,0], #4 [0,0,0,0,0,0,0,0,0,2], #5 [0,0,0,0,0,0,0,0,2,2], #6 [0,0,0,0,0,0,0,2,2,2], #7 [0,0,0,0,0,0,2,2,2,2], #8 [0,0,0,0,0,2,2,2,2,2]]) #9 chips1 = list(tuple(map(tuple,np.fliplr(np.argwhere(matrix == 1))))) #Finds all the positions that contain a 1 chips2 = list(tuple(map(tuple,np.fliplr(np.argwhere(matrix == 2))))) #Finds all the positions that contain a 2 print chips2 def step(x,y): #Finds the possible steps for a checker listMoves = [] if x > 0 and matrix[x-1][y] == 0: #left listMoves.append([x-1,y]) if x < 9 and matrix[x+1][y] == 0: #right listMoves.append([x+1,y]) if y < 9: #up if matrix[x][y+1] == 0: listMoves.append([x,y+1]) if x>0 and matrix[x-1][y+1] == 0: #up + left listMoves.append([x-1,y+1]) if x < 9 and matrix[x+1][y+1] == 0: #up + right listMoves.append([x+1,y+1]) if y > 0: #down if matrix[x][y-1] == 0: listMoves.append([x,y-1]) if x > 0 and matrix[x-1][y-1] == 0: #down + left listMoves.append([x-1,y-1]) if x<9 and matrix[x+1][y-1] == 0: listMoves.append([x+1,y-1]) return listMoves def hopper(x,y): #Finds the possible hops for a checker listHops = [] if x > 1 and matrix[x-1][y] != 0 and matrix[x-2][y] == 0: #left listHops.append([x-2,y]) if x < 8 and matrix[x+1][y] != 0 and matrix[x+2][y] == 0: #right listHops.append([x+2,y]) if y > 1: if matrix[x][y-1] != 0 and matrix[x][y-2] == 0: #down listHops.append([x,y-2]) if x>1 and matrix[x-1][y-1] != 0 and matrix[x-2][y-2] == 0: #down + left listHops.append([x-2,y-2]) if x < 8 and matrix[x+1][y+1] != 0 and matrix[x+2][y-2] == 0: #up + right listHops.append([x+2,y-2]) if y < 8: if matrix[x][y+1] != 0 and matrix[x][y+2] == 0: #up listHops.append([x,y+2]) if x > 1 and matrix[x-1][y+1] != 0 and matrix[x-2][y+2] == 0: #up + left listHops.append([x-2,y+2]) if x < 8 and matrix[x+1][y+1] != 0 and matrix[x+2][y+2] == 0: #up + right listHops.append([x+2,y+2]) listHops = listHops + step(x,y) return listHops ''' def flipBoard(): global matrix matrix = np.fliplr(np.flipud(matrix)) return matrix.tolist() flipBoard() ''' for i in range(0,len(chips2)): #loops through the list of positions to find all the possible steps and hops for print hopper(chips2[i][0], chips2[i][1])#every single checker on the board print matrix

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