Question

我正在做非常基本的PyQt所以请原谅可怜的优化和缺乏课程导向。

我试图在PyQt中制作一个计时器。我在UI上有3个LCD，一小时LCD（hourLcd），一分钟LCD（minuteLcd）和第二个LCD（secondLcd）

import sys
import time
from PyQt4 import QtGui
from PyQt4 import uic

app = QtGui.QApplication(sys.argv)
#window = QtGui.QMainWindow()

ui = uic.loadUi("clock.ui")

#ui.setupUi(Window)
ui.show()

这设置了PyQt4

def hourUp():
    count = ui.hourLcd.value()
    if count < 24:
        count = count + 1
    ui.hourLcd.display(count)

def hourDown():
    count = ui.hourLcd.value()
    if count > 0:
        count = count - 1
    ui.hourLcd.display(count)

def minuteUp():
    count = ui.minuteLcd.value()
    if count < 59:
        count = count + 1
    ui.minuteLcd.display(count)

def minuteDown():
    count = ui.minuteLcd.value()
    if count > 0:
        count = count - 1
    ui.minuteLcd.display(count)

def secondUp():
    count = ui.secondLcd.value()
    if count < 59:
        count = count + 1
    ui.secondLcd.display(count)

def secondDown():
    count = ui.secondLcd.value()
    if count > 0:
        count = count - 1
    ui.secondLcd.display(count)

这些是将UI按钮连接到动作的功能。例如如果您按下UI上的按钮，它会将一个添加到计数器

def start(stop):
    loop = False
    secondcounter = ui.secondLcd.value()
    minutecounter = ui.minuteLcd.value()
    hourcounter = ui.hourLcd.value()

    while loop == False:
        time.sleep(1)
        secondcounter = secondcounter - 1
        print(secondcounter)
        ui.secondLcd.display(secondcounter) ****

        if secondcounter == 0:
            if minutecounter != 0:
                minutecounter = minutecounter - 1
                print(minutecounter)
                ui.minuteLcd.display(minutecounter) ****
                secondcounter = secondcounter + 59
                ui.secondLcd.display(secondcounter) ****

        if secondcounter == 0:
            if minutecounter == 0:
                if hourcounter == 0:
                    loop = True

        if minutecounter == 0:
            if secondcounter == 0:
                if hourcounter != 0:
                    hourcounter = hourcounter - 1
                    print(hourcounter)
                    ui.hourLcd.display(hourcounter) ****
                    minutecounter = minutecounter + 59
                    print(minutecounter)
                    ui.minuteLcd.display(minutecounter) ****
                    secondcounter = secondcounter + 59
                    print(secondcounter)
                    ui.secondLcd.display(secondcounter) ****

        else:
            continue

使计时器工作的算法。

基本上，代码都完美无缺。它从给定的任何时间开始倒数到0，但是我无法将代码的打印输出链接到UI，特别是与它们旁边的星号相关的行。我不明白为什么代码在计数器改变时拒绝更新LCD数字（例如counter = counter-1，因为它在其他功能中起作用）。

谢谢！

Answer 1

找到解决方案。

 while loop == False:
    app.processEvents() #This was the line of code that I needed
    time.sleep(1)
    secondcounter = secondcounter - 1
    app.processEvents() #and this
    print(secondcounter)
    ui.secondLcd.display(secondcounter)

基本上，在调用你的ui

之前添加app.processEvents（）

LCD显示器不想更新输入（不显示我告诉它显示的内容）

1 个答案: