Question

我有以下两个对象：

var object1  = {
  "user1@yahoo.com": [
    {
      "status": "Unread",
      "message": "Some message 1",
      "senderId": "0063f297-0da6-4c23-9a53-0480c273d177",
      "id": "088b71bc-5b64-4f09-bba4-cf88b3cc598e",
      "time": "2016-05-13T10:30:11.495Z"
    },
    {
      "status": "Unread",
      "message": "Some other message 2",
      "senderId": "0063f297-0da6-4c23-9a53-0480c273d177",
      "id": "39b2850b-d8ac-4d23-9fa6-e7056fb6c030",
      "time": "2016-05-13T10:30:03.310Z"
    }
  ]
};

var object2 = {
  "user1@yahoo.com": [
    {
      "message": "Some message 1",
      "id": "088b71bc-5b64-4f09-bba4-cf88b3cc598e",
      "time": "2016-05-13T10:30:11.495Z"
    },
    {
      "message": "Some other message 2",
      "id": "39b2850b-d8ac-4d23-9fa6-e7056fb6c030",
      "time": "2016-05-13T10:30:03.310Z"
    }
  ],
  "user3@yahoo.com": [
    {
      "message": "Some message 1",
      "id": "088b71bc-5b64-4f09-bba4-cf88b3cc598e",
      "time": "2016-05-13T10:30:11.495Z"
    },
    {
      "message": "Some other message 1",
      "id": "39b2850b-d8ac-4d23-9fa6-e7056fb6c030",
      "time": "2016-05-13T10:30:03.310Z"
    }
  ]
};

我需要将它们组合成一个看起来像这样的对象：

var object3 = {
  "user1@yahoo.com": [
    {
      "status": "Unread",
      "message": "Some message 1",
      "senderId": "0063f297-0da6-4c23-9a53-0480c273d177",
      "id": "088b71bc-5b64-4f09-bba4-cf88b3cc598e",
      "time": "2016-05-13T10:30:11.495Z"
    },
    {
      "status": "Unread",
      "message": "Some other message 2",
      "senderId": "0063f297-0da6-4c23-9a53-0480c273d177",
      "id": "39b2850b-d8ac-4d23-9fa6-e7056fb6c030",
      "time": "2016-05-13T10:30:03.310Z"
    },
    {
      "message": "Some message 1",
      "id": "088b71bc-5b64-4f09-bba4-cf88b3cc598e",
      "time": "2016-05-13T10:30:11.495Z"
    },
    {
      "message": "Some other message 2",
      "id": "39b2850b-d8ac-4d23-9fa6-e7056fb6c030",
      "time": "2016-05-13T10:30:03.310Z"
    }
  ]
}

标识邮件组的电子邮件是相同的。

Answer 1

首先，从每个对象获取密钥。然后，对于两个对象中存在的每封电子邮件，连接其列表。

var keys1List = Object.getOwnPropertyNames(array1),
    keys2List = Object.getOwnPropertyNames(array2),
    result = {};

keys1List.forEach(function(email) {
    if (keys2List.indexOf(email) > -1) {
        result[email] = array1[email].concat(array2[email]);
    }
});

请注意，您的array1，array2和array3变量实际上是对象而不是数组。我建议你改变他们的名字，以便他们不会混淆其他人（甚至你，后来）会阅读这段代码。

Answer 2

var map = Object.keys(array1).reduce(function( map, email ) {
    map[email] = array1[email];
    if (array2.hasOwnProperty(email)) map[email] = map[email].concat(array2[email]);
    return map;
}, {});

Answer 3

这种组合就像你想要的那样：

Object.combineArrays = function(obj1, obj2) {
   var sizeA = 0, key, keyB;
   for (key in obj2) {
      if (obj1.hasOwnProperty(key) && obj2.hasOwnProperty(key)) {
        for (keyB in obj2[key]) {
           obj1['user1@yahoo.com'].push( obj2[key][keyB] );
        }
        sizeA++;
      }
   }
   return obj1;
};
var newObjects = Object.combineArrays(obj1, obj2);
console.log(newObjects);

Answer 4

使用下划线

_.mapObject(array1,function(val,key){
    return _.union(val,array2[key]);
})

结合两个多维数组内部值

4 个答案: