Question

我基于现有的第三方.NET Web服务创建了一个Java Web Service。这是我的网络服务界面：

package externalqueryadapter.service._01.responsereceiver;

import javax.jws.WebMethod;
import javax.jws.WebParam;
import javax.jws.WebService;
import javax.xml.bind.annotation.XmlSeeAlso;
import javax.xml.ws.Action;
import javax.xml.ws.RequestWrapper;
import javax.xml.ws.ResponseWrapper;
import org.datacontract.schemas._2004._07.commonservices_externalqueryadapter.ExternalResponse;

@WebService(name = "ResponseReceiver", targetNamespace = "http://Service.ExternalQueryAdapter/01/ResponseReceiver")
@XmlSeeAlso({
    externalqueryadapter.service._01.responsereceiver.ObjectFactory.class,
    org.datacontract.schemas._2004._07.commonservices_externalqueryadapter_contract.ObjectFactory.class
})
public interface ResponseReceiver {

    @WebMethod(operationName = "ReceiveResponse")
    @RequestWrapper(localName = "ReceiveResponse", targetNamespace = "http://Service.ExternalQueryAdapter/01/ResponseReceiver", className = "externalqueryadapter.service._01.responsereceiver.ReceiveResponse")
    @ResponseWrapper(localName = "ReceiveResponseResponse", targetNamespace = "http://Service.ExternalQueryAdapter/01/ResponseReceiver", className = "externalqueryadapter.service._01.responsereceiver.ReceiveResponseResponse")
    @Action(input = "http://Service.ExternalQueryAdapter/01/ResponseReceiver/ResponseReceiver/ReceiveResponseRequest", output = "http://Service.ExternalQueryAdapter/01/ResponseReceiver/ResponseReceiver/ReceiveResponseResponse")
    public void receiveResponse(
        @WebParam(name = "response", targetNamespace = "http://schemas.datacontract.org/2004/07/CommonServices.ExternalQueryAdapter.Contract")
        ExternalResponse response);
}

我的ExternalResponse课程

package org.datacontract.schemas._2004._07.commonservices_externalqueryadapter_contract;

import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlSchemaType;
import javax.xml.bind.annotation.XmlType;
import javax.xml.datatype.XMLGregorianCalendar;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "externalResponse", propOrder = {
    "requestTime",
    "userID"
})
public class ExternalResponse {

    @XmlSchemaType(name = "dateTime")
    protected XMLGregorianCalendar requestTime;
    protected String userID;

    public XMLGregorianCalendar getRequestTime() {
        return requestTime;
    }

    public void setRequestTime(XMLGregorianCalendar value) {
        this.requestTime = value;
    }

    public String getUserID() {
        return userID;
    }

    public void setUserID(String value) {
        this.userID = value;
    }
}

我成功地从Java WebService客户端接收SOAP消息，如下所示：

<soapenv:Envelope
    xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <soapenv:Body>
        <ReceiveResponse
            xmlns="http://Service.ExternalQueryAdapter/01/ResponseReceiver">
            <response
                xmlns="">
                <RequestTime>2013-01-30T20:00:00.000Z</RequestTime>
                <userID>olololo</userID>
            </response>
        </ReceiveResponse>
    </soapenv:Body>
</soapenv:Envelope>

但是如果SOAP消息包含响应参数的命名空间（它是来自第三方webService客户端的消息（我认为是.NET客户端）），我的Java WebService会在null中收到ExternalResponse响应。

<soapenv:Envelope
    xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <soapenv:Body>
        <ReceiveResponse
            xmlns="http://Service.ExternalQueryAdapter/01/ResponseReceiver">
            <response
                xmlns="http://schemas.datacontract.org/2004/07/CommonServices.ExternalQueryAdapter.Contract">
                <RequestTime>2013-01-30T20:00:00.000Z</RequestTime>
                <userID>olololo</userID>
            </response>
        </ReceiveResponse>
    </soapenv:Body>
</soapenv:Envelope>

package-info.java：

@javax.xml.bind.annotation.XmlSchema(namespace = "http://schemas.datacontract.org/2004/07/CommonServices.ExternalQueryAdapter.Contract", elementFormDefault = javax.xml.bind.annotation.XmlNsForm.QUALIFIED)
package org.datacontract.schemas._2004._07.CommonServices_ExternalQueryAdapter_Contract;

我的Java Web服务有什么问题？

Answer 1

您是否未能在档案中加入 package-info.class ？

由于非工作案例（包括TNS）与JAX-WS @WebParam匹配，我想知道你是否使用elementFormDefault =＆＃34; qualified＆＃34;生成了JAXB。（你通常可以在package-info.java中看到这个），但可能无法将它们压缩（或将它们加载到JAXBContext中），这可能会将elementFormDefault默认为不合格

如果这没有帮助，可能有助于粘贴WSDL / XSD并解释如何生成JAX-WS和JAXB注释类。使用 wsimport ？

Java Web Service：null请求参数

1 个答案: