Question

我是初学者，我无法弄清楚如何解决我的问题。

我有一个ManyToOne / OneToMany关联，我在表单类型中添加了一个字段，但handlerequest没有考虑关联，无论是在创建还是在编辑中。

我如何继续保存我的关联？

这是我的视频控制器

<?php

class VideoController extends Controller
{

... 

/**
 * Creates a new Video entity.
 *
 * @Route("/new", name="video_new")
 * @Method({"GET", "POST"})
 */
public function newAction(Request $request)
{
    $video = new Video();
    $form = $this->createForm('AppBundle\Form\VideoType', $video);
    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $em = $this->getDoctrine()->getManager();
        $em->persist($video);
        $em->flush();

        return $this->redirectToRoute('video_show', array('id' => $video->getId()));
    }

    return $this->render('video/new.html.twig', array(
        'video' => $video,
        'form' => $form->createView(),
    ));
}

/**
 * Displays a form to edit an existing Video entity.
 *
 * @Route("/{id}/edit", name="video_edit")
 * @Method({"GET", "POST"})
 */
public function editAction(Request $request, Video $video)
{
    $deleteForm = $this->createDeleteForm($video);
    $editForm = $this->createForm('AppBundle\Form\VideoType', $video);
    $editForm->handleRequest($request);

    if ($editForm->isSubmitted() && $editForm->isValid()) {
        $em = $this->getDoctrine()->getManager();
        $em->persist($video);
        $em->flush();

        return $this->redirectToRoute('video_edit', array('id' => $video->getId()));
    }

    return $this->render('video/edit.html.twig', array(
        'video' => $video,
        'edit_form' => $editForm->createView(),
        'delete_form' => $deleteForm->createView(),
    ));
}
...

}

现在是JT实体

namespace AppBundle\Entity;

use Doctrine\Common\Collections\ArrayCollection;

/**
 * JT
 *
 * @ORM\Table(name="j_t")
 * @ORM\Entity(repositoryClass="AppBundle\Repository\JTRepository")
 */
class JT
{

 ...

/**
 * @ORM\OneToMany(targetEntity="Video", mappedBy="jT")
 */
private $videos;

public function __construct()
{
    $this->products = new ArrayCollection();
}

/**
 * Add videos
 *
 * @param \AppBundle\Entity\Video $videos
 * @return JT
 */
public function addVideo(\AppBundle\Entity\Video $videos)
{
    $this->videos[] = $videos;

    return $this;
}

/**
 * Remove videos
 *
 * @param \AppBundle\Entity\Video $videos
 */
public function removeVideo(\AppBundle\Entity\Video $videos)
{
    $this->videos->removeElement($videos);
}

/**
 * Get videos
 *
 * @return \Doctrine\Common\Collections\Collection
 */
public function getVideos()
{
    return $this->videos;
}
}

视频实体

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Video
 *
 * @ORM\Table(name="video")
 * @ORM\Entity(repositoryClass="AppBundle\Repository\VideoRepository")
 */
class Video
{
    ....

          /**
         * @ORM\ManyToOne(targetEntity="JT", inversedBy="videos")
     * @ORM\JoinColumn(name="jT_id", referencedColumnName="id")
     */
    private $jT;



    /**
     * Set jT
     *
     * @param \AppBundle\Entity\JT $jT
     * @return Video
     */
    public function setJT(\AppBundle\Entity\JT $jT = null)
    {
        $this->jT = $jT;

        return $this;
    }

    /**
     * Get jT
     *
     * @return \AppBundle\Entity\JT
     */
    public function getJT()
    {
        return $this->jT;
    }


    /**
     * toString
     * @return string
     */
    public function __toString()
    {
        return $this->getTitle();
    }
}

最后，VideoType表格

class VideoType extends AbstractType
{
/**
 * @param FormBuilderInterface $builder
 * @param array $options
 */
public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder

        ...

        ->add('jT','entity'
                       ,array("label"=>"JT",
                              'label_attr' => array('class' => 'control-label'),
                              'class' => 'AppBundle:JT',
                              "attr"=>array("class"=>"form-control")
                      )
              );



}

我希望能够选择＆＃34;视频＆＃34;属于＆＃34; jT＆＃34;，以及视频形式中的哪一个。

PS：我怎么能添加一个＆＃34; none＆＃34;表格中的实体输入中的选项？

Answer 1

您有两个选择：

- 明确保存jT实体

$jT = $video->getJT();
$jT->addVideo($video);
$em->persist($jT);
$em->persist($video);
$em->flush();

- 为cascade persist配置实体

/**
 * @ORM\ManyToOne(targetEntity="JT", inversedBy="videos", cascade={"all"})
 * @ORM\JoinColumn(name="jT_id", referencedColumnName="id")
 */
private $jT;

public function setJT(JT $jT)
{
   $this->jT = $jT;

   $jT->addVideo($this)

   return $this;
}

/**
 * @ORM\OneToMany(targetEntity="Video", mappedBy="jT", cascade={"all"})
 */
private $videos;

后者的学说描述：http://doctrine-orm.readthedocs.io/projects/doctrine-orm/en/latest/reference/working-with-associations.html#association-management-methods

Synfony2 - 创造＆amp;编辑表单不持久关联

1 个答案: