我有一个数组看起来像:
Array
(
[0] => Array
(
[file_name] => Chrysanthemum13.jpg
[file_type] => image/jpeg
[file_path] => D:/wamp/www/multipleImage/upload/
[full_path] => D:/wamp/www/multipleImage/upload/Chrysanthemum13.jpg
[raw_name] => Chrysanthemum13
[orig_name] => Chrysanthemum.jpg
[client_name] => Chrysanthemum.jpg
[file_ext] => .jpg
[file_size] => 858.78
[is_image] => 1
[image_width] => 1024
[image_height] => 768
[image_type] => jpeg
[image_size_str] => width="1024" height="768"
)
[1] => Array
(
[file_name] => Desert6.jpg
[file_type] => image/jpeg
[file_path] => D:/wamp/www/multipleImage/upload/
[full_path] => D:/wamp/www/multipleImage/upload/Desert6.jpg
[raw_name] => Desert6
[orig_name] => Desert.jpg
[client_name] => Desert.jpg
[file_ext] => .jpg
[file_size] => 826.11
[is_image] => 1
[image_width] => 1024
[image_height] => 768
[image_type] => jpeg
[image_size_str] => width="1024" height="768"
)
)
我必须将 file_name 的值存储到数据库表中。 我的模特看起来:
public function galleryimages($image_data)
{
$data = array(
'image' => $image_data['file_name'],
);
$this->db->insert('gallery', $data);
}
我必须将 file_name 中的所有值存储到表image
的{{1}}中。我怎样才能成功呢?模型中需要进行哪些修改。
答案 0 :(得分:1)
您可以使用insert_batch通过一个查询插入所有行。
var container = $(".container"),
background = $(".background");
// ...
// Inside an each() method – check if is container OR background
if (this.is(container, background)) { // Not working
// do something
}
// I know I could do it like this ...
if (this.is(container) || this.is(background)) {
// do something
}
// ... but I want it shorter
答案 1 :(得分:0)
如果你可以在你的项目中做这样的事情:
//get the numbers of elements of the array
$array_len = count($image_data);
//create the $data array, which I suppose you want to have a associative key named 'images' to use it to insert to the database table.
for($i = 0; $i < $array_len; $i++) {
$data['images'][$i] = $image_data[$i]['file_name'];
}
//then insert each file name into the db.
foreach($data['images'] as $image) {
$this->db->insert('gallery', $image);
}
我假设您发布的var_dump()输出来自名为$ image_data的数组。