Question

我使用此查询获取最早的日期记录：

SELECT tt.*
FROM shop_meta tt
    INNER JOIN
        (SELECT seller_name, MIN(check_date) AS MinDateTime
         FROM shop_meta
         GROUP BY seller_name) groupedtt
    ON  tt.seller_name = groupedtt.seller_name
    AND tt.check_date = groupedtt.MinDateTime
order by seller_name

我试图在特定日期之后获得所有最早的日期记录。

我尝试添加：

having MIN(check_date) > $date

having groupedtt.MinDateTime > $date

having tt.check_date > $date

having check_date > $date

和

where MIN(check_date) > $date

where groupedtt.MinDateTime > $date

where tt.check_date > $date

where check_date > $date

在查询中order by之前，但我想我做错了。请帮忙！

编辑：

样本表：

seller_name status  check_date
Seller 1    open    2016-05-09
Seller 1    open    2016-05-25
Seller 1    open    2016-05-26
Seller 2    open    2016-05-10
Seller 2    open    2016-05-20
Seller 3    open    2016-05-09

预期结果为$date = 2016-05-19：

seller_name status  check_date
Seller 1    open    2016-05-25
Seller 2    open    2016-05-20

Answer 1

也许我错过了什么，但看起来很简单：

....
(SELECT seller_name, MIN(check_date) AS MinDateTime
 FROM   shop_meta
 WHERE  check_date > $date
 GROUP BY seller_name) groupedtt
....

Answer 2

    SELECT tt.*
    FROM shop_meta tt
    INNER JOIN
        (SELECT seller_name, MIN(check_date) AS MinDateTime
        FROM shop_meta
        GROUP BY seller_name
HAVING MIN(Check_date)>$date) groupedtt
    ON tt.seller_name = groupedtt.seller_name
    AND tt.check_date = groupedtt.MinDateTime order by seller_name

在特定日期

2 个答案: