我想获得iPhone的所有联系人列表。
我检查了Address Book
引用,我可能错过了一些内容,但我没有看到它提供了获取联系人列表的方法。
答案 0 :(得分:102)
在我的原始答案中,在这个答案的最后,我将展示如何在9.0之前的iOS版本中检索联系人,以解决其他答案所带来的一些问题。
但是,如果只支持iOS 9及更高版本,则应该使用Contacts
框架,避免使用较旧的AddressBook
框架时出现的一些烦人的桥接问题。
因此,在iOS 9中,您使用Contacts
框架:
@import Contacts;
您还需要更新Info.plist
,添加NSContactsUsageDescription
来解释您的应用需要访问联系人的原因。
然后执行以下操作:
CNAuthorizationStatus status = [CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts];
if (status == CNAuthorizationStatusDenied || status == CNAuthorizationStatusRestricted) {
UIAlertController *alert = [UIAlertController alertControllerWithTitle:@"Access to contacts." message:@"This app requires access to contacts because ..." preferredStyle:UIAlertControllerStyleActionSheet];
[alert addAction:[UIAlertAction actionWithTitle:@"Go to Settings" style:UIAlertActionStyleDefault handler:^(UIAlertAction * _Nonnull action) {
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString] options:@{} completionHandler:nil];
}]];
[alert addAction:[UIAlertAction actionWithTitle:@"Cancel" style:UIAlertActionStyleCancel handler:nil]];
[self presentViewController:alert animated:TRUE completion:nil];
return;
}
CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
// make sure the user granted us access
if (!granted) {
dispatch_async(dispatch_get_main_queue(), ^{
// user didn't grant access;
// so, again, tell user here why app needs permissions in order to do it's job;
// this is dispatched to the main queue because this request could be running on background thread
});
return;
}
// build array of contacts
NSMutableArray *contacts = [NSMutableArray array];
NSError *fetchError;
CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactIdentifierKey, [CNContactFormatter descriptorForRequiredKeysForStyle:CNContactFormatterStyleFullName]]];
BOOL success = [store enumerateContactsWithFetchRequest:request error:&fetchError usingBlock:^(CNContact *contact, BOOL *stop) {
[contacts addObject:contact];
}];
if (!success) {
NSLog(@"error = %@", fetchError);
}
// you can now do something with the list of contacts, for example, to show the names
CNContactFormatter *formatter = [[CNContactFormatter alloc] init];
for (CNContact *contact in contacts) {
NSString *string = [formatter stringFromContact:contact];
NSLog(@"contact = %@", string);
}
}];
如果支持iOS 9.0之前的iOS版本,以下是我的回答。
-
对您的问题以及此处提供的许多答案(无论是未能请求权限,不能正确处理ABAddressBookCreateWithOptions
错误或泄漏)的几个答案都有一些反应:
显然,导入AddressBook
框架:
#import <AddressBook/AddressBook.h>
或
@import AddressBook;
您必须请求该应用访问联系人的权限。例如:
ABAuthorizationStatus status = ABAddressBookGetAuthorizationStatus();
if (status == kABAuthorizationStatusDenied || status == kABAuthorizationStatusRestricted) {
// if you got here, user had previously denied/revoked permission for your
// app to access the contacts and all you can do is handle this gracefully,
// perhaps telling the user that they have to go to settings to grant access
// to contacts
[[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
return;
}
CFErrorRef error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
if (!addressBook) {
NSLog(@"ABAddressBookCreateWithOptions error: %@", CFBridgingRelease(error));
return;
}
ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
if (error) {
NSLog(@"ABAddressBookRequestAccessWithCompletion error: %@", CFBridgingRelease(error));
}
if (granted) {
// if they gave you permission, then just carry on
[self listPeopleInAddressBook:addressBook];
} else {
// however, if they didn't give you permission, handle it gracefully, for example...
dispatch_async(dispatch_get_main_queue(), ^{
// BTW, this is not on the main thread, so dispatch UI updates back to the main queue
[[[UIAlertView alloc] initWithTitle:nil message:@"This app requires access to your contacts to function properly. Please visit to the \"Privacy\" section in the iPhone Settings app." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
});
}
CFRelease(addressBook);
});
请注意,上面我没有使用别人建议的模式:
CFErrorRef *error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
这是不正确的。正如您在上面所见,您想要:
CFErrorRef error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, &error);
前一种模式不会正确捕获错误,而后者则会。如果error
不是NULL
,请不要忘记CFRelease
它(或像我一样将所有权转让给ARC),否则您将泄露该对象。
要遍历联系人,您需要:
- (void)listPeopleInAddressBook:(ABAddressBookRef)addressBook
{
NSArray *allPeople = CFBridgingRelease(ABAddressBookCopyArrayOfAllPeople(addressBook));
NSInteger numberOfPeople = [allPeople count];
for (NSInteger i = 0; i < numberOfPeople; i++) {
ABRecordRef person = (__bridge ABRecordRef)allPeople[i];
NSString *firstName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonFirstNameProperty));
NSString *lastName = CFBridgingRelease(ABRecordCopyValue(person, kABPersonLastNameProperty));
NSLog(@"Name:%@ %@", firstName, lastName);
ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
CFIndex numberOfPhoneNumbers = ABMultiValueGetCount(phoneNumbers);
for (CFIndex j = 0; j < numberOfPhoneNumbers; j++) {
NSString *phoneNumber = CFBridgingRelease(ABMultiValueCopyValueAtIndex(phoneNumbers, j));
NSLog(@" phone:%@", phoneNumber);
}
CFRelease(phoneNumbers);
NSLog(@"=============================================");
}
}
我想提请你注意一个相当关键的细节,即"Create Rule":
Core Foundation函数具有指示您拥有返回对象的名称:
名称中嵌入了“
Create
”的对象创建函数;名称中嵌入了“
Copy
”的对象复制功能。如果您拥有一个对象,那么当您完成它后,您有责任放弃所有权(使用CFRelease)。
这意味着您有责任通过名称中的Create
或Copy
释放任何Core Foundation功能返回的任何对象。您可以明确调用CFRelease
(正如我上面使用addressBook
和phoneNumbers
所做的那样),或者对于支持免费桥接的对象,您可以使用{{1}将所有权转移到ARC }或__bridge_transfer
(正如我上面的CFBridgingRelease
,allPeople
,lastName
和firstName
所做的那样。
静态分析器(在Xcode中按 shift + 命令 + B 或选择&#34;分析&#34;来自&# 34;产品&#34;菜单)可以识别您忽略的许多情况,并且#34;创建规则&#34;并且无法释放适当的对象。因此,每当编写像这样的Core Foundation代码时,请始终通过静态分析器运行它,以确保您没有任何明显的泄漏。
答案 1 :(得分:97)
也许ABPerson
函数ABAddressBookCopyArrayOfAllPeople可能会这样做?
ABAddressBookRef addressBook = ABAddressBookCreate( );
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople( addressBook );
CFIndex nPeople = ABAddressBookGetPersonCount( addressBook );
for ( int i = 0; i < nPeople; i++ )
{
ABRecordRef ref = CFArrayGetValueAtIndex( allPeople, i );
...
}
答案 2 :(得分:23)
使用此代码显示所有姓名+姓氏+电话号码(iOS 6)。也适用于模拟器:
CFErrorRef *error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);
for(int i = 0; i < numberOfPeople; i++) {
ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );
NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonFirstNameProperty));
NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonLastNameProperty));
NSLog(@"Name:%@ %@", firstName, lastName);
ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
NSString *phoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
NSLog(@"phone:%@", phoneNumber);
}
NSLog(@"=============================================");
}
答案 3 :(得分:12)
确保您拥有正确的导入
#import <AddressBook/AddressBook.h>
然后,您可以使用
获取所有联系人的CFArray对象CFArrayRef ABAddressBookCopyArrayOfAllPeople (ABAddressBookRef addressBook);
答案 4 :(得分:10)
在iOS 6中,请务必使用ABAddressBookCreateWithOptions
,ABAddressBookCreate
CFErrorRef * error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);
for(int i = 0; i < numberOfPeople; i++){
ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );
// More code here
}
答案 5 :(得分:9)
iOS 9.0
的 更新。 Apple已弃用AddressBook
,现在他们已添加Contacts
框架:
添加CNContactStore
属性并按以下方式定义:
self.contactsStrore = [[CNContactStore alloc] init];
然后添加这些方法以阅读所有联系人:
-(void)checkContactsAccess{
[self requestContactsAccessWithHandler:^(BOOL grandted) {
if (grandted) {
CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactNamePrefixKey, CNContactMiddleNameKey, CNContactPhoneNumbersKey]];
[self.contactsStrore enumerateContactsWithFetchRequest:request error:nil usingBlock:^(CNContact * _Nonnull contact, BOOL * _Nonnull stop) {
NSLog(@"%@", contact.familyName);
NSLog(@"%@", contact.givenName);
NSLog(@"%@", contact.namePrefix);
NSLog(@"%@", contact.middleName);
NSLog(@"%@", contact.phoneNumbers);
NSLog(@"=============================================");
}];
}
}];
}
-(void)requestContactsAccessWithHandler:(void (^)(BOOL grandted))handler{
switch ([CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts]) {
case CNAuthorizationStatusAuthorized:
handler(YES);
break;
case CNAuthorizationStatusDenied:
case CNAuthorizationStatusNotDetermined:{
[self.contactsStrore requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
handler(granted);
}];
break;
}
case CNAuthorizationStatusRestricted:
handler(NO);
break;
}
}
iOS 9.0之前=&gt;使用AddressBook
框架。
您必须首先检查访问权限并请求访问用户联系人:
// Prompt the user for access to their Address Book data
-(void)requestAddressBookAccess
{
YourViewController * __weak weakSelf = self;
ABAddressBookRequestAccessWithCompletion(self.addressBook, ^(bool granted, CFErrorRef error)
{
if (granted)
{
dispatch_async(dispatch_get_main_queue(), ^{
[weakSelf accessGrantedForAddressBook];
});
}
});
}
-(void)checkAddressBookAccess
{
switch (ABAddressBookGetAuthorizationStatus())
{
// Update our UI if the user has granted access to their Contacts
case kABAuthorizationStatusAuthorized:
[self accessGrantedForAddressBook];
break;
// Prompt the user for access to Contacts if there is no definitive answer
case kABAuthorizationStatusNotDetermined :
[self requestAddressBookAccess];
break;
// Display a message if the user has denied or restricted access to Contacts
case kABAuthorizationStatusDenied:
case kABAuthorizationStatusRestricted:
{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Privacy Warning"
message:@"Permission was not granted for Contacts."
delegate:nil
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
}
break;
default:
break;
}
}
答案 6 :(得分:7)
感谢mahesh和wzbozon,以下代码对我有用:
CFErrorRef * error = NULL;
addressBook = ABAddressBookCreateWithOptions(NULL, error);
ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error)
{
if (granted)
{
dispatch_async(dispatch_get_main_queue(), ^{
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);
for(int i = 0; i < numberOfPeople; i++){
ABRecordRef person = CFArrayGetValueAtIndex( allPeople, i );
NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonFirstNameProperty));
NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(person, kABPersonLastNameProperty));
NSLog(@"Name:%@ %@", firstName, lastName);
ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
NSMutableArray *numbers = [NSMutableArray array];
for (CFIndex i = 0; i < ABMultiValueGetCount(phoneNumbers); i++) {
NSString *phoneNumber = (__bridge_transfer NSString *) ABMultiValueCopyValueAtIndex(phoneNumbers, i);
[numbers addObject:phoneNumber];
}
NSMutableDictionary *contact = [NSMutableDictionary dictionary];
[contact setObject:name forKey:@"name"];
[contact setObject:numbers forKey:@"numbers"];
[all_contacts addObject:contact];
}
});
}
});
答案 7 :(得分:5)
Swift版本:
override func viewDidLoad() {
super.viewDidLoad()
var error: Unmanaged<CFErrorRef>?
var addressBook: ABAddressBook = ABAddressBookCreateWithOptions(nil, &error).takeRetainedValue()
if ABAddressBookGetAuthorizationStatus() == ABAuthorizationStatus.NotDetermined {
ABAddressBookRequestAccessWithCompletion(addressBook, {
(granted:Bool, error:CFErrorRef!) -> Void in
self.populateFrom(addressBook: addressBook)
})
}
else if ABAddressBookGetAuthorizationStatus() == ABAuthorizationStatus.Authorized {
self.populateFrom(addressBook: addressBook)
}
}
func populateFrom(#addressBook:ABAddressBook){
let allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook).takeRetainedValue()
let nPeople = ABAddressBookGetPersonCount(addressBook)
for index in 0..<nPeople{
let person: ABRecordRef = Unmanaged<ABRecordRef>.fromOpaque(COpaquePointer(CFArrayGetValueAtIndex(allPeople, index))).takeUnretainedValue()
let firstName: String = ABRecordCopyValue(person, kABPersonFirstNameProperty).takeUnretainedValue() as? String
println("\(firstName.debugDescription)")
}
}
答案 8 :(得分:4)
查看https://github.com/heardrwt/RHAddressBook(254星01/2014)。
为AddressBook提供一个ObjC包装器,其API更简单。
答案 9 :(得分:1)
这适用于ios 7和ios 8,我希望它可以帮助你.............
NSMutableArray *result = [[NSMutableArray alloc] init];
CFErrorRef *error = nil;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
__block BOOL accessGranted = NO;
if (ABAddressBookRequestAccessWithCompletion != NULL){
dispatch_semaphore_t sema = dispatch_semaphore_create(0);
ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
accessGranted = granted;
dispatch_semaphore_signal(sema);
});
dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
}
else{
accessGranted = YES;
}
if (accessGranted){
// If the app is authorized to access the first time then add the contact
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);
for (int i=0; i<numberOfPeople; i++){
CFStringRef phone;
ABRecordRef person = CFArrayGetValueAtIndex(allPeople, i);
CFStringRef firstName = ABRecordCopyValue(person, kABPersonFirstNameProperty);
CFStringRef lastName = ABRecordCopyValue(person, kABPersonLastNameProperty);
NSString *userName = @"NoName";
userName = [NSString stringWithFormat:@"%@ %@", firstName, lastName];
userName = [userName stringByReplacingOccurrencesOfString:@"(null)" withString:@""];
ABMutableMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
CFIndex phoneNumberCount = ABMultiValueGetCount( phoneNumbers );
phone = nil;
for ( CFIndex ind= 0; ind<phoneNumberCount; ind++ ){
CFStringRef phoneNumberLabel = ABMultiValueCopyLabelAtIndex( phoneNumbers, ind);
CFStringRef phoneNumberValue = ABMultiValueCopyValueAtIndex( phoneNumbers, ind);
// converts "_$!<Work>!$_" to "work" and "_$!<Mobile>!$_" to "mobile"
// Find the ones you want here
if (phoneNumberLabel != nil){
NSStringCompareOptions compareOptions = NSCaseInsensitiveSearch;
if(CFStringCompare(phoneNumberLabel, CFSTR("mobile"),compareOptions)){
phone = phoneNumberValue;
}
phone = phoneNumberValue;
NSStringCompareOptions compareOptionss = NSCaseInsensitiveSearch;
if(!CFStringCompare(phone, CFSTR("1-800-MY-APPLE"),compareOptionss)){
continue;
}
NSMutableArray *theKeys = [NSMutableArray arrayWithObjects:@"name", @"small_name",@"phone", @"checked", nil];
NSMutableArray *theObjects = [NSMutableArray arrayWithObjects:userName, [userName lowercaseString],phone, @"NO", nil];
NSMutableDictionary *theDict = [NSMutableDictionary dictionaryWithObjects:theObjects forKeys:theKeys];
if (![[functions formatNumber:(__bridge NSString *)(phone)] isEqualToString:[[NSUserDefaults standardUserDefaults]valueForKey:@"phoneNumber"]]){
[result addObject:theDict];
}
}
}
}
}
//sort array
NSSortDescriptor * descriptor = [[NSSortDescriptor alloc] initWithKey:@"small_name"
ascending:YES]; // 1
NSArray * sortedArray = [result sortedArrayUsingDescriptors:[NSArray arrayWithObject:descriptor]];
答案 10 :(得分:0)
ABAddressBookRef addressBook = ABAddressBookCreate( );
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople( addressBook );
CFIndex nPeople = ABAddressBookGetPersonCount( addressBook );
for ( int i = 0; i < nPeople; i++ )
{
ABRecordRef ref = CFArrayGetValueAtIndex( allPeople, i );
...
}
答案 11 :(得分:0)
这是一个完整的演示,用于获取具有表视图的所有联系人。
import UIKit
import ContactsUI
import AddressBook
import Contacts
class ShowContactsVC: UIViewController,CNContactPickerDelegate,UITableViewDelegate,UITableViewDataSource
{
@IBOutlet weak var tableView: UITableView!
let peoplePicker = CNContactPickerViewController()
let appDelegate = UIApplication.sharedApplication().delegate as! AppDelegate
var contacts = [CNContact]()
var option : Int = 0
var userAccessGranted : Bool = false
var dataArray : NSMutableArray?
override func viewDidLoad()
{
super.viewDidLoad()
peoplePicker.delegate = self
self.checkIfUserAccessGranted()
self.tableView.delegate = self
self.tableView.dataSource = self
navigationController!.navigationBar.barTintColor = UIColor.grayColor()
if(self.userAccessGranted)
{
self.tableView.hidden = false
fetchContacts()
}
}
func numberOfSectionsInTableView(tableView: UITableView) -> Int
{
return 1
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
if dataArray == nil {
return 0;
}
else{
return dataArray!.count
}
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell
{
let cell = tableView.dequeueReusableCellWithIdentifier("TableCell", forIndexPath: indexPath) as! ContactsTableViewCell
let data = dataArray![indexPath.row] as! Data;
cell.lblName.text = data.name
cell.imgContact.image = data.image
return cell
}
func tableView(tableView: UITableView, willDisplayCell cell: UITableViewCell, forRowAtIndexPath indexPath: NSIndexPath)
{
cell.backgroundColor = UIColor.cyanColor()
}
func checkIfUserAccessGranted()
{
appDelegate.requestForAccess { (accessGranted) -> Void in
if accessGranted {
self.userAccessGranted = true;
}else{
self.userAccessGranted = false;
}
}
}
func fetchContacts()
{
dataArray = NSMutableArray()
let toFetch = [CNContactGivenNameKey, CNContactImageDataKey, CNContactFamilyNameKey, CNContactImageDataAvailableKey]
let request = CNContactFetchRequest(keysToFetch: toFetch)
do{
try appDelegate.contactStore.enumerateContactsWithFetchRequest(request) {
contact, stop in
print(contact.givenName)
print(contact.familyName)
print(contact.identifier)
var userImage : UIImage;
// See if we can get image data
if let imageData = contact.imageData {
//If so create the image
userImage = UIImage(data: imageData)!
}else{
userImage = UIImage(named: "no_contact_image")!
}
let data = Data(name: contact.givenName, image: userImage)
self.dataArray?.addObject(data)
}
} catch let err{
print(err)
}
self.tableView.reloadData()
}
func contactPickerDidCancel(picker: CNContactPickerViewController)
{
picker.dismissViewControllerAnimated(true, completion: nil)
self.navigationController?.popToRootViewControllerAnimated(true)
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
import UIKit
class Data {
let name : String
let image : UIImage
init(name : String, image : UIImage) {
self.image = image
self.name = name
}
}
答案 12 :(得分:0)
如果要按字母顺序排序,可以使用下面的代码。
CFErrorRef *error = NULL;
ABAddressBookRef addressBook = ABAddressBookCreateWithOptions(NULL, error);
CFArrayRef allPeople = ABAddressBookCopyArrayOfAllPeople(addressBook);
CFIndex numberOfPeople = ABAddressBookGetPersonCount(addressBook);
CFMutableArrayRef peopleMutable = CFArrayCreateMutableCopy(kCFAllocatorDefault,
CFArrayGetCount(allPeople),
allPeople);
CFArraySortValues(peopleMutable,
CFRangeMake(0, CFArrayGetCount(peopleMutable)),
(CFComparatorFunction) ABPersonComparePeopleByName,
kABPersonSortByFirstName);